The problem is the number by the side
Answer:
1400m^2
Step-by-step explanation:
Solution,
Let the breadth of the rectangle be x m, then the length of the rectangle will be x+5 m,
Now,
Perimeter of the rectangle=2(l+b)
150=2(x+5+x)
150=2(2x+5)
150=4x+10
150-10=4x
140=4x
140/4=x
35=x
So, the breadth of the rectangle=35 m
and length=(35+5)m=40m
Again,
Area of the rectangle=l×b
=40m×35m
=1400 m^2
I hope it helped U
stay safe stay happy
2 units i believe but not entirely sure
Answer:
Step-by-step explanation:
a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.
b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.
c.) A red-black tree with 100,000 entries is 2 log 100, 000
d.) The worst-case height of T is 100,000.
e.) A binary search tree storing such a set would have a worst-case height of 100,000.
9514 1404 393
Answer:
6.2
Step-by-step explanation:
We presume your "k-value" is the k in the exponential decay term ...
e^(-kt) . . . where t is the number of time units
This is 1/2 when ...
ln(1/2) = -kt
t = ln(1/2)/(-k) = ln(2)/k
t = 0.69315/0.1124 ≈ 6.2
The half life is about 6.2 time units.
