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IceJOKER [234]
3 years ago
9

Are all rectangles similar

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
5 0
Yes. All rectangles are similar no matter how big or small they are (of course, they have to stay as a rectangle)

hope this helps
EastWind [94]3 years ago
3 0
Yes all rectangles are similar but not all are equal, (geometry)
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Please answer I keep wasting my points and getting ignored
Anna11 [10]

Answer:

205 square ft

Step-by-step explanation:

1. Since his room is 12ft by 15.75ft, we can multiply to find the square ft needed to cover his room.

2. Since his closet is 2ft by 8ft, we can multiply to find the square ft needed to cover his closet.

3. Then, we add them to find how much carpeting is needed total.

4. (12*15.75)+(2*8)=189+16=205

8 0
2 years ago
For brainiest:):):):):):):):)
Novosadov [1.4K]
H the hood and brown brown vented the hood of the hood and
8 0
3 years ago
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ANYONE...........help​
KATRIN_1 [288]

Answer:

  • 1 cm

Step-by-step explanation:

<u>Sides of the picture added margin:</u>

  • l = 8 + 2x
  • w = 5 + 2x
  • A(margin) = 30 cm²

<u>Solution</u>:

  • A(margin) = Total area - A(picture)
  • (8 + 2x)(5 + 2x) - 5*8 = 30
  • 4x² + 10x + 16x + 40 - 40 - 30 = 0
  • 4x² + 26x - 30 = 0
  • 2x² + 13x - 15 = 0
  • x = (-13 + √(13² + 2*4*15))/4
  • x = (-13 + 17)/4
  • x = 1 cm

Note. The other root is ignored as negative.

3 0
3 years ago
The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
3 years ago
I honestly don't know how I got these answers and I have a test over it coming soon. Please explain how to find the measure of t
Tju [1.3M]
Okay so a couple of things to know to best solve this problem
1) all angles in a triangle add to 180
2) a straight line the angles above it equal 180 and the angles below it add to 180
3) vertical angles are equal (vertical angles are angles that make an X the opposite angles are called vertical angles)
5 0
4 years ago
Read 2 more answers
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