Answer:
1.8.10=1.80000000000
7.2.10=7.2000000000
Step-by-step explanation:
Answer:
a)
H₀: ρ₁ ≤ ρ₂
H₁: ρ₁ > ρ₂
b)
Z= ![\frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} }](https://tex.z-dn.net/?f=%5Cfrac%7B%28%27p_%7B1%7D%20-%20%27p_%7B2%7D%29%20-%20%28p_%7B1%7D%20-%20p_%7B2%7D%29%7D%7B%5Csqrt%7B%27p%281-%27p%29%5B%5Cfrac%7B1%7D%7Bn_1%7D%20%2B%20%5Cfrac%7B1%7D%7Bn_2%7D%20%5D%7D%20%7D)
≈ N(0;1)
c)
p-value < .00001
d)
Reject the null hypothesis.
The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.
Step-by-step explanation:
Hello!
The objective is to test if the population proportion of vinyl gloves that leak viruses (population 1) is greater then the population proportion of latex gloves that leak viruses (population 2).
Sample 1 (Vinyl)
n₁= 225
Sample proportion 'ρ₁= 0.60
Sample 2 (Latex)
n₂= 225
Sample proportion 'ρ₂= 0.09
Pooled proportion: 'ρ= (x₁+x₂)/(n₁+n₂)= ( 'ρ₁ + 'ρ₂)/2= (0.60 + 0.09)/2= 0.345 ≅0.35
The hypothesis is:
H₀: ρ₁ ≤ ρ₂
H₁: ρ₁ > ρ₂
α: 0.05
The statistic to use is a pooled Z
Z= ≈ N(0;1)
The critical region is one-tailed to the right (positive), the critical value is:
If Z ≥ 1.64, you will reject the null hypothesis.
If Z < 1.64, you will not reject the null hypothesis.
Z= ![\frac{(0.6 - 0.09) - (0}{\sqrt{0.35(1-0.35)[\frac{1}{225} + \frac{1}{225} ]} }](https://tex.z-dn.net/?f=%5Cfrac%7B%280.6%20-%200.09%29%20-%20%280%7D%7B%5Csqrt%7B0.35%281-0.35%29%5B%5Cfrac%7B1%7D%7B225%7D%20%2B%20%5Cfrac%7B1%7D%7B225%7D%20%5D%7D%20%7D)
= 11.34
Since the calculated Z- value is greater than the critical value, the decision is to reject the null hypothesis. The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.
P-value approach:
p-value < .00001
If you compare with the level of signification, you reach the same decision.
I hope it helps!
Answer:
i belive the answer is 23
Step-by-step explanation:
You just have to divide then multiple by 100
Answer:
its c
Step-by-step explanation:
i think im sorry if it wrong this a unusal term for operation
Answer:
· Use properties of equality together to isolate variables and solve algebraic equations.
· Use the properties of equality and the distributive property to solve equations containing parentheses, fractions, and/or decimals.
Introduction
There are some equations that you can solve in your head quickly. For example – what is the value of y in the equation 2y = 6? Chances are you didn’t need to get out a pencil and paper to calculate that y = 3. You only needed to do one thing to get the answer, divide 6 by 2.
Other equations are more complicated. Solving without writing anything down is difficult! That’s because this equation contains not just a variable but also fractions and terms inside parentheses. This is a multi-step equation, one that takes several steps to solve. Although multi-step equations take more time and more operations, they can still be simplified and solved by applying basic algebraic rules.
Using Properties of Equalities
Remember that you can think of an equation as a balance scale, with the goal being to rewrite the equation so that it is easier to solve but still balanced. The addition property of equality and the multiplication property of equality explain how you can keep the scale, or the equation, balanced. Whenever you perform an operation to one side of the equation, if you perform the same exact operation to the other side, you’ll keep both sides of the equation equal.
If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division.
Step-by-step explanation:
