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just olya [345]

3 years ago

9

Find the equation of a line that bisects the line segment joining the points (-1, 3) and (5, -3) and intersects the x-axis at th

e origin.

1 answer:

maria [59]3 years ago

7 0

Answer:

x - axis or y = 0

Step-by-step explanation:

Bisector passes through the midpoint

(-1+5)/2, (3-3)/2

(2,0)

Line passing through (2,0) and the origin is the x-axis or y = 0

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Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the

love history [14]

Answer:

attached below

Step-by-step explanation:

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2 years ago

Inessa05 [86]

The question is an illustration of a division model.

The boxes will be completed with: 1650, 231, 50 and 7

The expression is represented as:

$\mathbf{1881 \div 33}$

Express 1881 as 1650 + 231.

$\mathbf{1881 \div 33 = (1650 + 231) \div 33}$

Split

$\mathbf{1881 \div 33 = 1650 \div 33 + 231 \div 33}$

Evaluate each division

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The above illustration means that, the boxes will be completed with the following numbers

1650
231
50
7

See attachment for proper illustration

Read more about division models at:

brainly.com/question/15163437

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1 year ago

Spiral Review Hayden is attending a craft show. The cost of an admission ticket is $8. The cost of a raffle ticket for a handmad

LekaFEV [45]

Answer:

7

Step-by-step explanation:

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3 years ago

If a polynomial cannot be written as the product of two other polynomials (excluding 1 and minus−1), then the polynomial is sa

Anni [7]

In mathematics, a polynomial is an algebraic expression containing more than two terms. When the polynomial could not be reduced to a lower degree, it is classified as a prime polynomial. Just like whole numbers, a prime polynomial cannot be broken down into factors except 1 and by the number itself. Take for example, the polynomial x² + 5x + 6. It can be reduces to its factors x=-2 and -3. That would be expressed to x² + 5x + 6 = (x+2)(x+3). But if the polynomial is, say, x² + 5x + 7, there is no roots that are whole numbers. Therefore, it can't be reduced into factored groups because it is a prime polynomial.

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2 years ago