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just olya [345]
3 years ago
9

Find the equation of a line that bisects the line segment joining the points (-1, 3) and (5, -3) and intersects the x-axis at th

e origin.
Mathematics
1 answer:
maria [59]3 years ago
7 0

Answer:

x - axis or y = 0

Step-by-step explanation:

Bisector passes through the midpoint

(-1+5)/2, (3-3)/2

(2,0)

Line passing through (2,0) and the origin is the x-axis or y = 0

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How do I find the arc from a central angle?
Lesechka [4]

Answer:

Divide the central angle in radians by 2 and perform the sine function on it. Divide the chord length by double the result of step 1. This calculation gives you the radius. Multiply the radius by the central angle to get the arc length.

8 0
2 years ago
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The length of a rectangle is 3 inches more than the width. The area is 10 square inches. Find the dimensions
mr_godi [17]

Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

   L be the length of the rectangle

   w be the width of the rectangle

<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0  

<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 =  0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2

  or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5

-5 is not valid ,because w represents the width

which must be a positive number

Then  w = 2

<u><em>Conclusion</em></u>:

Width = 2

Length = 2 + 3 = 5

6 0
2 years ago
-(2x + y) +3 (x - 4y)
Elanso [62]
X-13y is the answer to that equation
5 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20252%5C%5C" id="TexFormula1" title="\sqrt{x} 252\\" alt="\sqrt{x} 252\\" align
Firlakuza [10]

Answer:

does it say simplify or no ? :|

Step-by-step explanation:

7 0
2 years ago
Find the area of a parallelogram. If base = 15 cm; height= 5 cm
Romashka [77]
75


Base * Height = area
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3 years ago
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