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LenKa [72]
3 years ago
8

Please help!!! Algebra 1

Mathematics
1 answer:
Fed [463]3 years ago
4 0
Can you send again the pic
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Help please I’m confused
tiny-mole [99]
3y= 21

I think 3y would be 21 because in the equation, 5y+13=48, y= 7. So if we know that y is 7 that’ll mean we’ll use 7 to interpret y for 3y.
3 0
3 years ago
HELP ASAP OFFERING 13 points
dsp73

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find f(g(-4)) if f(x) =7/x+2<br> and g(x) = (x + 5)^2. Options: -5/2 , -7/2 , 37/4 , 7/3
aev [14]

Answer:

7/3

Step-by-step explanation:

f(x) =7/(x+2)

g(x) = (x + 5)^2

f(g(-4))=

First find g(-4)

g(-4) = (-4+5)^2

        =(1)^2 =1

Then find f(1)

f(1)= 7/(1+2)

   = 7/3

5 0
3 years ago
Will mark brainliest and thank you!!! Please help!
Usimov [2.4K]
The correct answer is maybe 3
7 0
3 years ago
Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are
Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0
3 years ago
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