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astraxan [27]
3 years ago
13

Find the mean for the following data set: 5, 3, 6, 8, 1, 1 *

Mathematics
2 answers:
Zarrin [17]3 years ago
8 0

Answer:

add all the numbers

which will get you 24

then divide by how many numbers you got which will give you 6

the answer is six

Step-by-step explanation:

Hope this helps :D

Serga [27]3 years ago
3 0

Answer:

The mean is equal to 4.

Step-by-step explanation:

To find the mean of any set of numbers, you have to add all of those numbers and divide the result by however many numbers their are.

For example, the mean of 2,5,6, and 7 would be the following: 2+5+6+7/4

The mean of 5,3,6,8,1, and 1 is the following: 5+3+6+8+1+1/6=24/6=4

The mean is equal to 4.

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Wouldn't you subtract 35 by 7.

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Solve four tenths plus four ninths
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Help me with these questions
Elena L [17]

Answer: a = 4, b = 163,422

<u>Step-by-step explanation:</u>

P = P_{0} e^{kt}   P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.

Part a) What do we know?

P = 7003

P₀ = unknown

k = .21 <em>(converted 21% into a decimal)</em>

t = 36 yrs <em>(2006 - 1970) </em>

P = P_{0} e^{kt}   <em>need to solve for P₀</em>

7003 = P_{0} e^{(.21)(36)}

7003 = P_{0} e^{7.56}

7003 = P₀ (1920)

\frac{7003}{1920} = P_{0}

3.6 = P₀

rounded to the nearest whole number = 4

Part b) What do we know?

P = unknown

P₀ = 7003

k = .21 <em>(converted 21% into a decimal)</em>

t = 15 yrs <em>(2021 - 2006) </em>

P = P_{0} e^{kt}   <em>need to solve for P₀</em>

P = 7003 e^{(.21)(15)}

P = 7003 e^{3.15}

P = 7003(23.33)

P = 163,422.46

rounded to the nearest whole number = 163,422

*************************************************************

Answer: 2, -1

<u>Step-by-step explanation:</u>

eˣ² = eˣ * e²

eˣ² = eˣ⁺²

x² = x + 2

x² - x - 2 = 0

(x - 2)(x + 1) = 0

x - 2 = 0      or      x + 1 = 0

 x = 2          or         x = -1

Check both answer for validity:

eˣ² = eˣ⁺²

e⁴ = e⁴     or   e¹ = e¹

TRUE             TRUE

*****************************************

Answer: 0 = ln 1

<u>Step-by-step explanation:</u>

e^{-10} = \frac{1}{e^{10}}

ln(e^{-10}) = ln(\frac{1}{e^{10}})

-10 = ln 1 - 10   <em>log rules say division is subtraction</em>

 0 = ln 1



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