Answer:
The given line segment whose end points are A(2,2) and B(3,8).
Distance AB is given by distance formula , which is
if we have to find distance between two points (a,b) and (p,q) is
= ![\sqrt{(p-a)^2+(q-b)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28p-a%29%5E2%2B%28q-b%29%5E2%7D)
AB=
= 6.08 (approx)
Line segment AB is dilated by a factor of 3.5 to get New line segment CD.
Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)
Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)
CD = AB × 3.5
CD = √37× 3.5
= 6.08 × 3.5
= 21.28 unit(approx)
2. Slope of line joining two points (p,q) and (a,b) is given by
m=![\frac{q-b}{p-a}](https://tex.z-dn.net/?f=%5Cfrac%7Bq-b%7D%7Bp-a%7D)
m= ![\frac{8-2}{3-2}=6](https://tex.z-dn.net/?f=%5Cfrac%7B8-2%7D%7B3-2%7D%3D6)
As the two lines are coincident , so their slopes are equal.
Slope of line AB=Slope of line CD = 6