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2 years ago

Which number is a natural number? 10 5.5 –45 0

Mathematics

1 answer:

ehidna [41]2 years ago

8 0

A natural number is 10

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What conclusion can you make about the result of adding a rational and an irrational number?

aivan3 [116]

Answer:

It is irrational

Step-by-step explanation:

if you combine a rational and irrational number it cannot be rational.

6 0

3 years ago

Read 2 more answers

An archaeologist is categorizing the artifacts he has discovered. Two-thirds of the artifacts are shards of pottery. One-eighth

Reika [66]

Answer:

Personal items=15

Step-by-step explanation:

We are given:

Total number of artifacts = 72.

We are told that 2/3 of total artifacts are shards of pottery.

$\text{Shards of pottery}=72*\frac{2}{3} =24*2=48$

We are also told that 1/8 of total artifacts are tools.

$\text{Tools}=72*\frac{1}{8}=9$

Now we will find out number of personal items by subtracting combined number of shards of pottery and tools from total number of artifacts.

$\text{ Personal items}=72-(48+9)$

$\text{ Personal items}=72-57=15$

Therefore, there are 15 personal items.

8 0

3 years ago

I am on my trigonometry unit in math and don’t know what to do for this. I also really need work shown!

soldi70 [24.7K]

Answer:

The flight was 137.45 miles farther than the direct path.

(make slight changes if directions were given on how to round. This is to the nearest hundredth)

Step-by-step explanation:

Use the Law of Cosines.

c^2=

a^2+b^2-2abcosC

You know two sides and the angle in between. The Law of Cosines will give us the third side.

The third side is the direct path of the airplane. We'll add the two other given sides to find the detour route that they took instead.

Then subtract the smaller number (direct route) from the actual route. See image.

8 0

2 years ago

How many times as great is the diameter of a pinhead as the diameter of a cloud-water droplet

Ulleksa [173]

Given:

The diameter of cloud-water droplet is

$10^{-5}$

The diameter of pinhead is 0.001.

Explanation:

Divide the dimater of cloud-water droplet by dimater of pinhead to determine the times as great is the diameter of a pinhead as the diameter of a cloud-water droplet .

$\begin{gathered} a=\frac{0.001}{10^{-5}} \\ =0.001\cdot10^5 \\ =100 \end{gathered}$

So diameter of a pin-head is 100 times the diameter of water-droplet.

5 0

1 year ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago