Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
Answer:
n = 5
Step-by-step explanation:
Hope this helps.
Answer:
3x
Step-by-step explanation:
Answer:
Step-by-step explanation:
The shape consists of three parts: a half sphere, a round cylinder and a round cone.
The half sphere volume = 1/2 * 4/3 * π * (4)^3
= 32/3 π
The round cyllinder volume = π * (4)^2 * 10
= 160 π
The round cone volume = 1/3 * π * (4)^2 * 3
= 16 π
Adding them together, the volume of shape
= 32/3 π + 160π + 16π
= (32/3 + 160 + 16)*3.14
= 586.13
Similarly the surface area
= (4π4^2)/2 + 2π4*10 + π*4*5
= (32+80+25)*3.14
= 430.18
Answer:
download photomath
Step-by-step explanation:
