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3 years ago

8

A transformation involves a shape being_, shifted or _____

1 answer:

TiliK225 [7]3 years ago

7 0

Translated and rotated or the answer to your question I hope you get 100 on this

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Is 0.047 1/100 of 4.70

LiRa [457]

Answer:

Yes!

Step-by-step explanation:

4.70 (1/100) = 4.70(.01) = .047

6 0

3 years ago

Read 2 more answers

What is the common denomination for 3/10 and 9/8

4vir4ik [10]

Answer:

80

Step-by-step explanation:

because if you want to find a common denimeter we have mulitly the deometer to find the answer

sorry if it is wrong

8 0

2 years ago

Let F be a field, and suppose a EF, a *0. Prove that a has a unique multiplicative inverse.

bezimeni [28]

Answer with Step-by-step explanation:

Let F be a field .Suppose $a\in F$ and $a\neq 0$

We have to prove that a has unique multiplicative inverse.

Suppose a has two inverses b and c

Then, $ac=1,ab=1$ where 1 =Multiplicative identity

$ac=ab$

$c=b$ (cancel a on both sides)

Hence, a has unique multiplicative inverse.

6 0

3 years ago

A customer purchased a total of 23 hamburgers and chicken sandwiches. Each hamburger costs $3.50 and each chicken sandwich costs

Bezzdna [24]

Answer:

25 2/7

Step-by-step explanation:

88.50/3.50 divide 88.50 by 3:50

6 0

3 years ago

The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

$V = \frac{4}{3}\pi \cdot r^{3}$

$A_{s} = 4\pi \cdot r^{2}$

a) The volume of the sphere is:

$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

$A_{s} = 5026.548\,in^{2}$

c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

$\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)$

$\Delta V = 150.796\,in^{3}$

$\Delta A_{s} = 8\pi\cdot r \,\Delta r$

$\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)$

$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

$\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%$

$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

4 0

3 years ago