Please somone help me 40 points will mark brainliest
2 answers:
1. We're doubling to go from ABDC to A'B'D'C'. So AB=15 becomes A'B'=30 cm and BD=8 becomes B'C'=16 cm. Please see attached figure.
2. We have equal ratios
40:50:60 = 30:37.5:45
Let's check that. 30/40=3/4, 37.5/50=3/4, 45/20=3/4, all ratios the same, similar triangles.
We see the meets of the longest side and the shortest side are B and Z respectively.
The meets of the longest side and the medium side are C and X.
The meets of the short side and medium side are A and Y.
Pairing them up we have our
Answer: ABC ~ YZX
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Given the figure of a square pyramid
The area pf the base =area of the square of side 14 in =
the area of the sides = 4 times the area of a triangle of a base of 14 in and a height of 12 in
so, the area of the sides =
So, the surface area of the pyramid =
So, the answer will be A = 532 in^2
since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side
now, let us use the pythagorean theorem, to find the opposite side, or "b"
so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means, -15 = b
so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then