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3 years ago

I need help with these 2 questions.

Mathematics

1 answer:

ahrayia [7]3 years ago

7 0

Answer:

Step-by-step explanation:

6). Surface area of a triangular prism = Area of the triangular bases + (Perimeter of the triangular base)×height

Area of one triangular base = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}\times 4\times 3$

= 6 km²

Perimeter of the triangular base = (4 + 3 + 5)

= 12 km

Height of the triangular prism = 7 km

Surface area of the given triangular prism = 2(6) + (12)(7)

= 12 + 84

= 96 km²

7). Surface area of a rectangular prism = 2(lb + bh + hl)

Here, l = Length, b = Width and h = Height

By substituting the values from the given question,

l = 9 in, b = 9 in, h = 4 in

Surface area of the rectangular prism = 2(9×9 + 9×4 + 4×9)

= 2(81 + 36 + 36)

= 2(153)

= 306 in²

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3 years ago

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Permutations are used when order is important so, as in the given question order is required. We would use permutations

The formula used is: $^nP_r=\frac{n!}{(n-r)!}$ where:

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$^nP_r\\^{15}P_3=\frac{15!}{(15-3)!} =2730 \ ways$

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3 years ago

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4 years ago

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