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2 years ago

If y varies directly with x and y=20.4 when x=6, find the value of y when x=-5?

Mathematics

2 answers:

Svetlanka [38]2 years ago

8 0

Answer:

A. Y=17

Step-by-step explanation:

Hope this helps

a_sh-v [17]2 years ago

4 0

Answer:

y=-17

Step-by-step explanation:

y=mx

20.4=m×6

20.4÷6=m

3.4=m

y=3.4×-5

y=-17

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sergij07 [2.7K]

Answer:

less than or equal to

Step-by-step explanation:

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2 years ago

(-9x - 4) - (4x2 + 2x - 7)

yaroslaw [1]

Answer:

I assume you meant 4x^2

So the answer in simplified form is -4x^2-11x+3

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Question 6

likoan [24]

The answer is B 20,250 cm

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2 years ago

A red ant travels 9/8 inches in 3/4 minutes and 3 3/8 inches in 2 1/4 minutes what is the ants speed in inches per minute? What

I am Lyosha [343]

Answer:

1. 1.5 inches per minute

2. 90 inches per hour

Step-by-step explanation:

speed = $\frac{distance}{time}$

1. total distance covered = $\frac{9}{8}$ + $\frac{27}{8}$

= $\frac{9+27}{8}$

= $\frac{36}{8}$

= 4 $\frac{1}{2}$ inches

Total time taken = $\frac{3}{4}$ + $\frac{9}{4}$

= $\frac{3 +9}{4}$

= $\frac{12}{4}$

= 3 minutes

The ants average speed = $\frac{4.5}{3}$

= 1 $\frac{1}{2}$

= 1.5

The ants speed is 1 $\frac{1}{2}$ inches per minute.

2. Since;

60 minutes = 1 hour

3 minutes = x hours

x = $\frac{3}{60}$

= $\frac{1}{60}$

= 0.05 hours

Speed = $\frac{4.5}{0.05}$

= 90 inches per hour

The red ants speed is 90 inches per hour.

3 0

2 years ago

An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week

sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) = (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0

2 years ago