Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Answer:
⟨-5, -1⟩
Step-by-step explanation:
Vector:
A vector is given by its endpoint subtracted by its initial point.
Vector u has initial point at (3, 9) and terminal point at (–7, 5)
Then
Vector v has initial point at (1, –4) and terminal point at (6, –1).
Then
What is u + v in component form?
⟨-5, -1⟩ is the answer.
Answer:
In word form it would be 2 to the 6th power.
Step-by-step explanation:
We know this because exponent equals to 2*2*2*2*2*2 or also known as 2 to the 6th power.
I can help but what is the (2)???
Answer:
32
Step-by-step explanation:
The shape in image is an equilateral triangle which means all of it's angles has equal measurements:
2x - 4 = 5y and that is equal to 60 degrees
2x - 4 = 60 add 4 to both sides
2x = 64 divide both sides by 2
x = 32
