Write the equation of the graph in vertex form enter power using ^ and don’t forget y or f(x)

HELP. Pleaseee. I have no idea what this means.

Vilka [71]

Answer:

2

Step-by-step explanation:

roots are the intercepts at the x axis I believe

8 0

3 years ago

Write and evaluate an expression for the area of a circular pizza.

Annette [7]

Area is the PRODUCT (multiply!) of the SQUARE of the radius and pi.

$A=\pi r^2$

In the diagram, the radius of the pizza is 7 in., so use r = 7.

$A = (3.14)(7^2) = (3.14)(49) = 153.86$ square inches.

7 0

3 years ago

A rectangle is 10 feet long by 2 feet wide.

Montano1993 [528]

Answer:

14 ft²

Step-by-step explanation:

To find the area of a rectangle you multiply the length and width. Sense the length is 10 feet but 3 feet was removed it is now 7 feet. Now you multiply that 7 feet by the width of 2 feet to get

7×2=

Area= 14 ft²

4 0

2 years ago

A zookeeper predicted the weight of a new baby elephant to be 261 pounds when it was born. The elephant actually weighed 293 pou

Papessa [141]

Percent error=| $\frac{predicted value-actual value}{predicted value}$ | times 100
(note the || is absolute value, means that whatever the result is inside, it is made positive)

predicted value=261
actual value=293
subsitute
percent error=| $\frac{261-293}{261}$ | times 100
so using pemdas
do parenthasees first
| $\frac{-32}{261}$ |
|-0.12|
absolute value
0.1226

time 100
0.1226 times 100=12.26
answer is 12.26%
answer is B

8 0

3 years ago

Teen obesity:

Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample % of U.S. public high school students who were obese = 15%

n = sample of U.S. public high school students = 300

p = population percentage of all U.S. public high school students

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ , $0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ ]

= [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0

3 years ago