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Vaselesa [24]
3 years ago
11

Identify the system of equations used to solve the following problem. A laboratory employee is mixing a 10% saline solution with

4% saline solution. How much of each solution is needed to make 500 milliliters of a 6% solution?

Mathematics
1 answer:
irakobra [83]3 years ago
7 0
I think with the kinds of mixture problems, it's really helpful to make a table.

The equations you actually need are x + y = 500 and 0.1(500-y)+0.04y=30. Since I was so close, I went ahead and just solved it anyway. You can see my setup on the attached image.

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No one is answering i posted this question 2 times, this is my 3rd time please answer.
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Answer:

13

Step-by-step explanation:

First, fill in 3 boxes of the table using the given information (blue numbers on the attached table)

"Of the 32 students that have a cell phone, 19 students do not have a tablet."

The top row of the table is students who have a cell phone.  Therefore, place 19 in the box in this row that is in the "no tablet" column.

"Of the 70 students that have a tablet, 57 students do not have a cell phone."

The first column of the table is students who have a tablet.  Therefore, place 57 in the box in the 2nd row of this column.

"11 students do not have a cell phone or a tablet."

Find the "no cell phone" row and the "no tablet" column and place 11 in the box that coincides.

We can calculate the blank totals using addition (shown by green numbers on the attached table)

  • Total students with no cell phone = 57 + 11 = 68
  • Total students with no tablet = 19 + 11 = 30

To calculate the number of students who have a cell phone AND a tablet:

⇒ Total students with a cell phone <em>minus</em> students with a cell phone but no tablet

⇒ 32 - 19 = 13

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