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mafiozo [28]
3 years ago
12

Josephine lives in a

Mathematics
1 answer:
REY [17]3 years ago
8 0
My guess is 17 i really dont knowwww
You might be interested in
Please help me asap!
Firdavs [7]

Answer:

Option d) 115 degrees

Step-by-step explanation:

We are given a trapezium ABDE in the picture.  AB and ED are the parallel sides.

F is the mid point of AE and C the midpoint of BD.  FC is joined.

We are also given that angle of AED = 65 degrees.

To find the measure of angle BAE.

Since sides AB and ED are parallel sides we find that AE is the transvesal intersecting the two parallel lines.

Hence by parallel lines axiom, the two interior angles namely Angle AED and BAE are supplementary.

i.e. 65 +angle BAE=180

Hence angle BAE = 115 degrees.

Option d is the answer.

7 0
3 years ago
Draw out a two column proof for each problem below. Complete all problems on one page and upload ONE photo of the entire assignm
Hunter-Best [27]

Two or more <u>triangles</u> are <em>congruent </em>if on comparison, they have equal lengths of <u>sides,</u> and measure of <u>angles</u>.

Therefore, the required proofs for each question are shown below:

Problem 1:

<em>Congruent triangles</em> are <u>triangles</u> with equal lengths of <em>corresponding</em> <u>sides</u> and measures of internal <u>angles</u>.

Thus,

                     STATEMENT                          REASON

1. <NMQ ≅ <NPQ                            Any point on a <em>perpendicular bisector</em>      

                                                        makes <u>equal</u> measure of angle with the

                                                        two ends of the<em> line</em> segment.

2. NQ ⊥ MP                                     Definition of a<u> line</u>.

3. MQ ≅ PQ                                     <em>Equal segments</em> of a bisected <u>line</u>.

4. MN ≅ PN                                     Any point on a <em>perpendicular bisector </em>    

                                                        is at the same <u>distance</u> to the

                                                        two ends of the <em>line segment</em>.

5. <MNQ ≅ <PNQ                           <u>Equal</u> measure of the <u>bisected</u> angle.

Problem 2:

A line <em>segment</em> is the shortest <u>distance</u> between two points.

            STATEMENTS                    REASONS

1. m<PSR  ≅ m<PSQ                A <em>perpendicular bisector </em>is always at a right  

                                                  angle to the <u>bisected</u> <em>line segment</em>.

2. m<RPS ≅ m<QPS                 Equal measure of the <u>bisected</u> <em>angle</em>.

3. RS ≅ QS                                Property of a <u>bisected</u> <em>line</em> segment.

4. PR ≅ PQ                                Any point on a <em>perpendicular bisector </em>    

                                                  is at the same <u>distance</u> to the two ends of  

                                                 the <u>line</u> segment.

For more clarifications on the perpendicular bisector of a line segment, visit: brainly.com/question/12475568

#SPJ1

3 0
2 years ago
What are the soltions to the innequality -7x+14 is grater than -3x-6
hichkok12 [17]

-7x+14>-3x-6

Add 3x to both sides

-7x+14+3x>-3x-6+3x

-4x+14>-6

Subtract 14 from both sides

-4x+14-14>-6-14

-4x>-20

Divide both sides by -4

-4x/4>-20/-4

x<5


I hope that's help , please let me know !

7 0
3 years ago
Find the missing measurement of AC
IgorLugansk [536]

Answer:

AC = 78

Step-by-step explanation:

Since all the angles are equal (60°), this is an equiangular triangle (meaning all angles re equal). Equiangular triangles are also equilateral meaning that all sides are equal)

We are given then one side is 11x-32 and another side is 5x+28

These two sides must be equal so we can set them equal to each other and solve for x

11x - 32 = 5x + 28

6x - 32 = 28

6x = 60

x = 10

If x = 10, then we can substitute x into either of the two equations to find the length of all three sides (since all sides have equal length)

11(10)-32 = 110 - 32 = 78

AB = BC = AC = 78

AC = 78

8 0
3 years ago
If 15 percent of the sixth graders have blonde hair, and there are 120 sixth graders, how many of them have blonde hair?
Vlada [557]
15/100 = 0.15 x 120 = 18
8 0
4 years ago
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