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mafiozo [28]
3 years ago
12

Josephine lives in a

Mathematics
1 answer:
REY [17]3 years ago
8 0
My guess is 17 i really dont knowwww
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gail works for a vending company. she gets paid $64 per week plus 20% of her total salesm how much will her total sales for the
denis23 [38]
At least 680 in sales because 200$-64$ is 136. 136*5=680 because 136 is one fifth or 20% of 680
4 0
3 years ago
I have no idea what to do with this someone help
joja [24]
The given distance of 5.20 would be A.

Replace A with 5.20 to solve for T.

T = 5.20^3/2
T = 11.9 years.
4 0
3 years ago
Read 2 more answers
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
Vlad1618 [11]

Answer:

Option B. b\geq 9

Step-by-step explanation:

Let

b------> the number of buses

we know that

48b\geq (412+20) -----> inequality that represent the situation

Solve for b

48b\geq 432

b\geq 432/48

b\geq 9

6 0
3 years ago
Read 2 more answers
Solve for x.
lidiya [134]

Answer:

x = 1/4

Step-by-step explanation:

<u>Calculations:</u>

7(x-3)+3(4-x)=-8

7x-21+12-3x=-8

4x-9=-8

4x=1

x=\frac{1}{4}

7 0
3 years ago
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