Answer:
D' = ( -3, -2)
Step-by-step explanation:
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Answer:
x = 1/5 , and x = - 1/5
Step-by-step explanation:
25x² – 1 = 0
5²x² - 1² = 0
(5x - 1)(5x + 1) = 0
5x -1 = 0, 5x + 1 = 0
x = 1/5 , x = - 1/5
Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
Answer:
257
General Formulas and Concepts:
Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Define</u>
2x² + 5x + 7
x = 10
<u>Step 2: Evaluate</u>
- Substitute: 2(10)² + 5(10) + 7
- Exponents: 2(100) + 5(10) + 7
- Multiply: 200 + 50 + 7
- Add: 250 + 7
- Add: 257
Answer:
It's the 5+(-3)
Step-by-step explanation:
