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natali 33 [55]
3 years ago
13

The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima

tely equal? Y = 1/x+2 Y=x^2+2

Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0

Answer:

The solution to this system of equations is -1.811.

Step-by-step explanation:

The given system of equations is

y=\frac{1}{x+2}

y=x^2+2

Graph these function on a coordinate plane. The x-coordinate of intersection points of both functions are solutions of the given system of equations.

The graph of both functions is given below.

From the below graph it is clear that the intersection point of both the function is (-1.811,5.278).

Therefore the solution to this system of equations is -1.811.

drek231 [11]3 years ago
3 0
Hello,
\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\



x=-1.81053571 and y=<span> 5,27803957 </span>

Download xls
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Find the slope and the y-intercept of the line with the given equation.
sladkih [1.3K]

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Step-by-step explanation:

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8 0
3 years ago
In △ABC, AB = 13.2m,
luda_lava [24]

Answer:

(i) ∠ABH  = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding  ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH  = 180°  (Sum of interior angle in a polygon)

46° + <HBC  + 90 = 180°

 <HBC+ 136°  = 180°

subtract 136 from both-side of the equation

 <HBC+ 136° - 136°  = 180° -136°

 <HBC  = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

\frac{sin A}{a} =  \frac{sin C}{c}

A = ?

a=6.9

C=90

c=13.2

\frac{sin A}{6.9} = \frac{sin 90}{13.2}

sin A = 6.9 sin 90  /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC  = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC  + 121.5°  = 180°

subtract 121.5° from both-side of the equation

<ABC  + 121.5° - 121.5°  = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

           =58.5° - 44°

            =14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180°  ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB  = 134°

Using sine rule,

\frac{sin 134}{13.2}  = \frac{sin 14.5}{AH}

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

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Can anyone help??
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make two triangles. make the bottom of one triangle 135 as the shadow and "x" as the height. the other traingle should have 9 at the bottom and 5.3 as the height. then make a proportion

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