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tresset_1 [31]
3 years ago
14

Round to nearest tenth

Mathematics
1 answer:
Goshia [24]3 years ago
6 0

Answer:

Step-by-step explanation:

this is exactly the same as the 1st one,  just  they put it in a different orientation.   sooo use law of cosines , where

QR = c

a = 12

b = 23

cos(120) = cos (P)

c = sq rt [ a^2+b^2﹣2*a*b*cos(P) ]

QR = sq rt [ 12^2 + 23^2 - 2* 12*23*cos(120) ]

QR = sq rt [ 144 + 529 - 552 * (-0.5 0 ]

QR = sq rt [ 673 + 276 ]

QR = sq rt [ 949 ]

QR = 30.8058

rounded to nearest 10th is

QR = 30.8  :)

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One week Beth bought 3 apples and 8 pears for $14.50. The next week she bought 6 apples and 4 pears and paid $14. Find the cost
zalisa [80]
Let us assume the cost of 1 apple = x dollars
Let us also assume the cost of 1 pear = y dollars
Then we can form two equations from the details given in the question. Based on those details the required answer to the question can be easily deduced.
3x + 8y = 14.50
And
6x + 4y = 14
Dividing both sides of the equation by 2 we get
3x + 2y = 7
2y = 7 - 3x
y = (7 - 3x)/2
Putting the value of y from the second equation in the first equation we get
3x + 8y = 14.50
3x + 8[(7 - 3x)/2] = 14.50
3x + 4 (7 - 3x) = 14.50
3x + 28 - 12x = 14.50
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9x = 13.5
x = 13.5/9
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Putting the value of x in the second equation we get
6x + 4y = 14
(6 * 1.5) + 4y = 14
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4y = 14 - 9
4y = 5
y = 5/4
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So we can find from the above deduction that the cost of 1 apple is 1.5 dollars and the cost of 1 pear is 1.25 dollars
Then
Cost of 2 apples = 2 * 1.5 dollars
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So the cost of 2 apples is $3 and the cost of 1 pear is $1.25.
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