Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer:
Is there supost to be an image or options orrr?....
Step-by-step explanation:
You need to post the figure?
Answer:
To find the solutions to the following questions what you would need to do is to factor out the common variable or g. Which would be the following:
g(g-4) = 45
g = 45
g2 = 49
This is more of the erraneous way to find the solution for the original one factor the expression
Step-by-step explanation:
g2 - 4g - 45 = 0
(g-9)(g+5) = 0
you can figure out what the 2 roots would be.
