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Valentin [98]
2 years ago
7

What is the gradient of the blue line, maths watch

Mathematics
1 answer:
Alborosie2 years ago
4 0
No picture? what’s the question
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A regular hexagon has an apothem measuring 14 cm and an approximate perimeter of 96 cm.
Mariulka [41]

ANSWER

672cm²

EXPLANATION

The area of a regular hexagon is given by the formula,

Area =  \frac{1}{2} ap

where a=14cm is the apothem and p=96cm is the perimeter of the regular hexagon.

We substitute the values into the formula,

Area =  \frac{1}{2}  \times 14 \times 96 {cm}^{2}

Area =672 {cm}^{2}

Therefore the approximate area of the hexagon is 672cm²

8 0
3 years ago
Read 2 more answers
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
Find the equivalent exponential expression (4^4)^2
sdas [7]
<span>(4^4)^2
= 4^(4*2)
=4^8

answer
4^8</span>
3 0
2 years ago
Read 2 more answers
8th GRADE MATH
s2008m [1.1K]
The answer for the question is a
6 0
1 year ago
Read 2 more answers
Jonathan took 33 pictures on the class trip and 67
Semenov [28]

Answer:

<em>JONATHAN WILL NEED 14 PAGES.</em>

Explanation:

<em>33 + 67 = 100</em>

<em>100 - 12 = 88</em>

<em>88 ÷ 6 = 14.6666667 </em>

<em>14.6666667 ⇒ </em><u><em>14</em></u>

<em>(Round 14.6666667 down to 14 because Johnathan does not have .6666667 of a page.)</em>

<em></em>

3 0
2 years ago
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