Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
Answer:
Solution given:
y=25 [base side of isosceles triangle]
sin 45=opposite/hypotenuse
sin45=25/x
x=25/sin45
x=25√2
Answer:
x=13 degrees
Step-by-step explanation:
Since m is parallel to l, 119= (9x+2)
119=9x+2
Subtract 2
117=9x
Divide by 9
13=x
Answer:
5. 76
6. 24
Step-by-step explanation:
5.
x + x = 152
2x = 152
x = 76
6.
2x + 3x = 120
5x = 120
x = 24
Answer:
(-14,-4)
Step-by-step explanation:
Given the pre-image A=(-7,-2)
If A is dilated with a scale factor of 2
Then the image of A,
A' = (-7,-2) X 2
We multiply each coordinate point by 2
=(-7*2,-2*2)=(-14,-4)
Therefore, the point A' would be: (-14,-4)
