We are given with two equations and is asked to determine the solution of the system of linear equation. via elimination, we add the two equations to eliminate 3x, this means y should be equal to 9 and from the first equation, x should also be equal to 9, too
let's do 1, 5, 6, 10 and 13.
1)
well, the denominator is the same on each, so we simply have to look at the numerator, who is larger 3 or 5? 3 < 5, 3 is less than 5, so then........
5)

6)
we can make both denominators the same if we simply <u>multiply each fraction by the other's denominator</u>.

10)
we'll convert the mixed fractions to improper fractions first, then make their denominator the same just like we did in 6).
![\bf \stackrel{mixed}{4\frac{1}{7}}\implies \cfrac{4\cdot 7+1}{7}\implies \stackrel{improper}{\cfrac{29}{7}}~\hfill \stackrel{mixed}{3\frac{3}{18}}\implies \cfrac{3\cdot 18+3}{18}\implies \stackrel{improper}{\cfrac{57}{18}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} \cfrac{29}{7}\cdot \cfrac{18}{18}\implies \cfrac{522}{126} \\\\\\ \cfrac{57}{18}\cdot \cfrac{7}{7}\implies \cfrac{399}{126} \end{cases}\qquad \implies \cfrac{522}{126}>\cfrac{399}{126}\qquad therefore\qquad 4\frac{1}{7}>3\frac{3}{18}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B1%7D%7B7%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%207%2B1%7D%7B7%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B29%7D%7B7%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B3%7D%7B18%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%2018%2B3%7D%7B18%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B57%7D%7B18%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20%5Ccfrac%7B29%7D%7B7%7D%5Ccdot%20%5Ccfrac%7B18%7D%7B18%7D%5Cimplies%20%5Ccfrac%7B522%7D%7B126%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B57%7D%7B18%7D%5Ccdot%20%5Ccfrac%7B7%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B399%7D%7B126%7D%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%20%5Ccfrac%7B522%7D%7B126%7D%3E%5Ccfrac%7B399%7D%7B126%7D%5Cqquad%20therefore%5Cqquad%204%5Cfrac%7B1%7D%7B7%7D%3E3%5Cfrac%7B3%7D%7B18%7D)
13)
so both fractions are at a value from 9, so we can simply say, which is larger 2/6 or 4/12?

Answer:
6xy²+7-x²y²-5x²y+3x²y²=6x²+7+2x²y²-5x²y
Answer:
I would say just take the big number and subtract the 41??...
Answer:
I'm going to write both of these because maybe you have a fill in the blank question. I don't know.

Simplify:

Step-by-step explanation:
is the equation of a circle with center (h,k) and radius r.
You are given (h,k)=(4,5) because that is the center.
You are given r=9 because it says radius 9.
Let's plug this in.

Simplify:
