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Zarrin [17]
3 years ago
15

Pls help me with this math problem​

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0

Answer:

The four rational numbers between -\frac{1}{2} and \frac{1}{2} can be:

  • -\frac{1}{3}
  • -\frac{1}{4}
  • \frac{1}{5}
  • \frac{1}{7}

Step-by-step explanation:

The definition of rational numbers is usually a number of the type a/b where b is different from zero, therefore, to choose the numbers that are between -1/2 (= -0.5) and 1/2 (= 0.5) <u><em>it is enough with choose fractional numbers whose dividend is 1 and its divisor is any number greater than 2, either negative or positive,</em></u> in the answer we choose options such as 1/7 or -1/3, but following the guide I give you, you could choose numbers like 1/16, -1/9 or 1/40 if you wish, always respecting the guidelines given for the dividend and the divisor.

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12. What's the simplified form of x − 1 + 4 + 7x − 3?
Leviafan [203]
The first one is B and the second is D
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4 years ago
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Write the following numbers in order of size.<br> Start with the smallest number.<br> -6, 6,-5,0,12
Scorpion4ik [409]

Answer:

-6,-5,0,6,12

Step-by-step explanation:

The negative numbers are obviously smaller than the positive ones :)

4 0
3 years ago
Read 2 more answers
I need help fast. please help me​
galina1969 [7]

<em>ANSWER :</em>

<u><em></em></u>

<em>I THINK ITS B </em>

<u><em></em></u>

EXPLANATION :

<u><em>ANSWERED BY THE BEST !!!!</em></u>

<u><em></em></u>

<em>        </em><u><em>ANGIEEEEEE <3 </em></u>

<u><em></em></u>

<em>HOPE YOU DO WELL ON YOUR ASSIGNMENT !!!!!  <3</em>

7 0
4 years ago
Read 2 more answers
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
Assume that the random variable X is normally distributed, with mean 60 and standard deviation 16. Compute the probability P(X &
elixir [45]

Answer:

P(X < 80) = 0.89435.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 60, \sigma = 16

P(X < 80)

This is the pvalue of Z when X = 80. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 60}{16}

Z = 1.25

Z = 1.25 has a pvalue of 0.89435.

So

P(X < 80) = 0.89435.

5 0
3 years ago
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