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3 years ago

What is the slope of the line passing through (1, 2) and (3, 8)? A: slope = 1/7 B: slope = 1/3 C: slope = 3 D: slope = 7

Mathematics

2 answers:

Aliun [14]3 years ago

5 0

Slope = (y2-y1)/(x2-x1) = (8-2)/(3-1) = 6/2 = 3. So the answer is c.

Alexxandr [17]3 years ago

3 0

Answer: m=3

Step-by-step explanation: Slope is equal to the change in y over the change in x, or rise over run. The change in x is equal to the difference in x-coordinates (also called run), and the change in y is equal to the difference in y-coordinates (also called rise). The formula to solve this is m=y2-y1/x2-x1. then you substitute in the values of x and y into the equation to find the slope. now your problem should look like this... m=8-(2)/3-(1)... Then you simplify. simplify both numerator and denominator which should leave you with... m=6/2... then you just divide and get m=3

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Step-by-step explanation:

(1/12)^-2b x 12^-2b+2=12

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Step-by-step explanation:

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Answer:

$\frac{r}{3\pi h+r}$

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

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$A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}$

Now, area of 2 cylinders would be the formula:

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So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm divided by A_total.

Shown below:

$\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}$

We simplify further:

$\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}$

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Answer:

Step-by-step explanation:

let the 2 digit number be ab = 10a + b ( considering place value )

The reversed 2 digit number is ba = 10b + a

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a = 12 - b → (1)

Expressing as an equation

ba = ab + 54 , that is

10b + a = 10a + b + 54

Substitute a = 12 - b into the equation

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