Ask question

Ask question

All categories

3 years ago

7

What is the process to correctly divide 58.19 by 2.74 without a calculator?

2 answers:

Alja [10]3 years ago

7 0

Move the decimal point to the right twice to get rid of decimal

3819/274

solve

your answer should be 13.94 rounded up

hope this helps

Anastaziya [24]3 years ago

5 0

Answer:

Without calculator divide 58.19 by 2.74 is nearest to 20.

Step-by-step explanation:

To find : What is the process to correctly divide 58.19 by 2.74 without a calculator?

Solution :

We have to divide 58.19 by 2.74,

We apply rounding numbers to make it a whole number which can easily be divide.

Rounding 58.19 to the nearest tens is 60.

Rounding 2.74 to the nearest tenth is 3.

So, divide 60 by 3

$\frac{60}{3}=20$

Approximately without calculator divide 58.19 by 2.74 is nearest to 20.

You might be interested in

I need help solving question 56, 58 and 59.

Colt1911 [192]

56a. 3000(1+.06)^5= 4014.67
56b. 3000(1+(.06/2))^5= 3477.82
56c. 3000(1+(.06/12))^5= 3075.75
56d. 3000e^(0.06•5)= 4049.57

58a. When placed in a scientific calculator and finding the ExpReg, you get the equation 50•2.828^x, so you take 2.828 and turn that in to a percentage so it’ll be about 2.83%.
58b. 50
58c. 50•2.828^t
58d. 50•2.828^4.5= about 5,378 bacteria
58e. Putting the equation and 50,000 into a graphing calcultor and finding the intersect of their graphs shows that after about 6.64 hours, the bacteria will reach that number.

59a. Set the equation to 150,000 (the triple of 50,000) and solve it, so it’ll start off as 50,000(1+(0.075/4))^x=150,000. The answer will be about 59.1 years.
59b. Do the same as the last question, except with the equation 50,000e^(0.075•x). The answer will be about 14.6 years.

7 0

3 years ago

9.8x10^6 In standard form

liraira [26]

What do you think? Hint 6 pi

6 0

3 years ago

Read 2 more answers

An individual repeatedly attempts to pass a driving test. Suppose that the probability of passing the test with each attempt is

vladimir1956 [14]

Answer:

a) Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

b) $P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

c) $P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number of trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Part a

Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

Part b

We want this probability:

$P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

We find the individual probabilities like this:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

Part c

For this case we want this probability:

$P(X \geq 5)$

And we can use the complement rule like this:

$P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

3 0

3 years ago

A to the 5th power times a to the -3 power

olasank [31]

A to the second power is the answer to this problem

8 0

4 years ago

HELP FAST!!!!!!!!!!

Alenkinab [10]

X - the percent of increase

$210+210x=260 \\
210x=260-210 \\
210x=50 \\
x=\frac{50}{210} \\
x \approx 0.238 \\
x \approx 23.8\%$

The percent of increase is approximately 23.8%.

5 0

3 years ago