Answer:
The particle will travel 6 feet in first 2 seconds.
Step-by-step explanation:
We have been given that a particle moves according to the velocity equation
. We are asked to find the distance that the particle will travel in its first 2 seconds.


Now, we will eliminate the absolute value sign as:

![s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B%5Cfrac%7B6t%5E3%7D%7B3%7D-%5Cfrac%7B18t%5E2%7D%7B2%7D%2B12t%5D%5E1_0%20%2B%5B%5Cfrac%7B-6t%5E3%7D%7B3%7D%2B%5Cfrac%7B18t%5E2%7D%7B2%7D-12t%5D%5E2_1)
![s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B2t%5E3-9t%5E2%2B12t%5D%5E1_0%20%2B%5B-2t%5E3%2B9t%5E2-12t%5D%5E2_1)





Therefore, the particle will travel 6 feet in first 2 seconds.
Answer:
y = 5.543
Step-by-step explanation:
Your y = 7(1 - 0.021)^11 is evaluated as follows:
y = 7(0.979)^11
y = 7(0.7918
y = 5.543
Answer:
In 1942 , the U.S. Mint produced 154,500,000 nickels. The scientific notation of 154,500,000 is obtained as
.
Step-by-step explanation:
- In the problem, it is given that in 1942, the U.S. Mint produced 154,500,000 nickels.
- It is required to write 154,500,000 in scientific notation.
- To solve this first, move the decimal point so that the first factor is greater than or equal to 1 also it should be less than 10.
- Count the number of decimal places n, and write the number as a product with a power of 10. Then check the answer.
Step 1 of 2
Obtain the scientific notation.
Here the original number, 154,500,000 is greater than 1 so we will have a positive power of 10 .
Move the decimal point to get 1.545, a number between 1 and 10 . Then we get,
1.54500000
The count of the number of decimal places the point was moved is 8 .
Write as a product with a positive power of 10 .

Step 2 of 2
Check the answer.
Rewrite and simplify to check our answer.

No, 10”3 is equal too 1000. 10”2 is equal too 100
The answer is four because you solve simplify the equation given and W could equal 4 or -5, and since the width can not be a negative number it has to be 4.