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3 years ago

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Which side in the image corresponds to Side length T V in the pre-image? Side length U T Side length V U Side length T S Side le

ngth T V

1 answer:

marshall27 [118]3 years ago

4 0

Answer:

Answer: The side in the image that corresponds to Side length TV in the pre-image is TV

Step-by-step explanation:

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Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)

TEA [102]

Answer:

<h2> $a. \: {x}^{2} + 2$ </h2>

<h2> </h2><h2> $b. \: 2 {x}^{2} - 5x$ </h2><h2> </h2><h2> $c. \: 6 {x}^{2} + 8x$ </h2><h3> </h3><h3> $d. \: 6 {x}^{2} - 12x$ </h3>

solution,

$a. \: x(x + 2) \\ \: \: = x \times x + 2 \times x \\ \: \: = {x}^{2} + 2x$

$b . \: x(2x - 5) \\ \: = x \times 2x - x \times 5 \\ \: \: = 2 {x}^{2} - 5x$

$c. \: 2x(3x + 4) \\ \: = 2x \times 3x + 2x \times 4 \\ \: \: = 6 {x}^{2} + 8x$

$d. \: 6x(x - 2) \\ \: \: = 6x \times x - 6x \times 2 \\ \: \: = 6 {x}^{2} - 12x$

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0

3 years ago

What is the scale factor of the dilation? Help please

DaniilM [7]

Imagine A'V' is part of the dilated figure, and AV is part of the original figure.

A'V' = 3.2

AV = 3.2 + 4.8 = 8

A'V'/AV = 3.2/8 = 2/5

Answer: First choice, 2/5.

4 0

3 years ago

Please solve thank you Jesus loves you

34kurt

The correct answer would be B

4 0

3 years ago

Raul calculated that he would spend $125 on school supplies this year but he accually spent 87.50 on school supplies what is his

sergey [27]

Fraction of his error= 87.50/ $125
=0.7
Percentage= 0.7 * 100
= 70%

5 0

3 years ago

I have two question whoever answers both can have the brainliest and 20 points

mina [271]

The answer for ''4x = 5x - 12'' would be x = 12.

4x - 5x = 12 (subtract 5x from both sides)

-x = -12 (simplify 4x - 5x to -x)

x = -12 ( multiply both sides by -1) .

For the 2nd one ''10p + 5 = 18p - 6/2''

The answer is 1 not those choices

10p + 5 = 18p - 3

5 = 18p - 3 - 10p

5 = 8p - 3

5 + 3 = 8p

8 = 8p

1 = p

p = 1.

3 0

3 years ago