cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
Answer:
a) y=2x+4 b) 2 c) 6 d) Sorry, you'll have to do that buy it's not too difficult! ^u^
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
1a) Well, if you add the y to both sides, you would get y=2x+4
1b) Since the main form is y=mx+b with m being the slope, the slope in y=2x+4 must be 2
1c) 6, because if x is 1, 2(1)+4=6
1d) I'm afraid you'll have to do that, just substitute in different numbers for x
(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥
Please, please give brainliest, it would be greatly appreciated, I only need one more before I advance, thanks!
What is that supposed to mean
