Consecutive integers are 1 more than the other.
If one of them is x.
The three would be x, x + 1, x + 2
Since the sum are 138
x + (x + 1) + (x +2) = 138
x + x + 1 + x +2 = 138
x + x + x + 1 + 2 = 138
3x + 3 = 138
3x = 138 - 3
3x = 135
x = 135/3
x = 47.
So the numbers are, x, x + 1, x + 2, = 47, 47 + 1 = 48, 47 + 2 = 49
The integers are 47, 48, and 49.
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Answer:
Step-by-step explanation:
Answer:
n = 0 or 10
Step-by-step explanation:
From the question,
Equation of the circle = (x-1)²+(y-5)² = 50 ............... Equation 1
Coordinate of the circle = (6,n)
From the question
x = 6, y = n
Substitute the value of x and y into equation 1
(6-1)²+(n-5)² = 50
5²+(n-5)² = 50
25+(n-5)² = 50
(n-5)² = 50-25
(n-5)² = 25.
Solving for n
n-5 = √(25
n-5 = ±5
Either,
n-5 = -5
n = -5+5
n = 0
or
n-5 = +5
n = 5+5
n = 10
Answer:
Step-by-step explanation:
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