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3 years ago

A swimming pool is 25 yards long. How many feet long is the swimming pool.

Mathematics

2 answers:

Charra [1.4K]3 years ago

8 0

Answer:

75 ft

Step-by-step explanation:

25 x 3 = 75; 3 ft in each yard multiplied by the 25 yds.

maks197457 [2]3 years ago

3 0

Answer:

The answer to your question is 75

Step-by-step explanation:

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What is the graph of 5x+4y>2

AfilCa [17]

Answer:

Attached you will find the red area to describe the equation 5x + 4y >2.

Which can also be easily reduced to y> 1/2 - 5/4x.

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What are the coordinates of the vertex of the graph of y = x2 + 8x + 1?

Rus_ich [418]

Answer:

y= x2 + 8x - 1 is y=(x+4) 2-17

Step-by-step explanation:

First find - b/2 = - 4, so -4 will be added to x inside the parenthesis.

Next , find c - b2 to find the value you added at the end

y= (x- b2) 2 + c - b2

y= (x+4) 2 - 17

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3 years ago

Find an equation of the plane that contains (3, 4, −9) and is parallel to x + y − 5z = 1. (Use x, y, and z for coordinates.)

emmainna [20.7K]

Answer:

x + y - 5z = 52

Step-by-step explanation:

Given data:

Point on the plane (3,4,-9)

parallel to x + y -5z = 1

Finding the normal vector

(1 , 1 , -5)(x, y , z) = 1

the normal vector is (1 , 1 , -5)

<em>formula for finding equation the plane given the normal vector (a,b,c) and point (m,n,o) is as </em>

Substituting the data we have

1(x-3) + 1( y- 4) - 5(z+9) =0

x-3 +y -4 -5z -45 = 0

x + y - 5z = 45 +4 +3

x + y - 5z = 52

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3 years ago

Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2

Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$ .

The sine difference identity is:

$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

We need to find a way to put some or all of these together to get:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$ .

So I do notice on the right hand side the $\sin(a+b)$ and the $\sin(a-b)$ .

Let's start there then.

There is a plus sign in between them so let's add those together:

$\sin(a+b)+\sin(a-b)$

$=[\sin(a+b)]+[\sin(a-b)]$

$=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]$

There are two pairs of like terms. I will gather them together so you can see it more clearly:

$=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]$

$=2\sin(a)\cos(b)+0$

$=2\sin(a)\cos(b)$

So this implies:

$\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)$

Divide both sides by 2:

$\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)$

By the symmetric property we can write:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$

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3 years ago

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olga nikolaevna [1]

I think the answer is 1.5

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3 years ago

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A swimming pool is 25 yards long. How many feet long is the swimming pool.​

A swimming pool is 25 yards long. How many feet long is the swimming pool.