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snow_tiger [21]
3 years ago
15

Write an Equation given the point (1, -1) and a rate of 2.

Mathematics
2 answers:
KonstantinChe [14]3 years ago
5 0
Y = mx + b

plug in the numbers to find b

-1 = 2(1) + b

simplify

-1 = 2 + b
-3 = b

write out the equation with the new info

the answer should be:
y = 2x - 3
Verizon [17]3 years ago
4 0

Answer:

y+1=2(x-1)

Step-by-step explanation:

use point slope form

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line m passes through point (-2,-1) and is perpendicular to the graph of y=-2/3x+6. Line n is parallel to line m and passes thro
puteri [66]

Answer:

Hello...... here is a solution :

1 -  

Hello:

the   equation of "m" is : y = ax+b

the slope is a : a×(- 2/3) = -1......( perpendicular to a line : y=-2/3x+6 when the slope is -2/3 )

a = 3/2          

the line " n" that passes through (4, - 3) and  parallel to line "m" :  

when the slope is 3/2 ( same slope )

the equation in slope-intercept form of the line" n" is :

 y – (-3)= (3/2)(x – 4)







7 0
3 years ago
Read 2 more answers
I NEED HELP THIS IS LATE
slamgirl [31]

Answer:

M=-10

Step-by-step explanation:

To find the sope we use y-y1/x-x1. For this problem, I chose the first two coordinates.

(-33.5)-(-55.6)/1.20-3.45=22.6/-2.25=-10(rounded)

hope this helps!:)

6 0
3 years ago
Find the surface area of the cone in terms of pi.​
gayaneshka [121]

Answer:

33π FT^2

Step-by-step explanation:

A=πr(r+(h2+r2)^1/2)

= π3(3+8)

=33π

8 0
3 years ago
Determine whether the sequence below is a geometric sequence and, if so, find a formula that describes the sequence. 1, 3, 9, 27
Dmitry_Shevchenko [17]
This is geometric  with a common ratio of 3   (3/1 = 3 and 9/3 = 3 etc)
the formula for the nth term is 
an = 3^(n-1)
3 0
3 years ago
In the diagram below, lines a and b are parallel and cut by transversal, t. If angle 3 is 120 degrees, find the measure of angle
PolarNik [594]
Hi there!

Since angles 3 and 7 are corresponding angles, they are also congruent. This means that angle 3 is equal to angle 7. Therefore, the correct answer is C, 120 degrees.
4 0
3 years ago
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