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julsineya [31]
2 years ago
9

Without doing any calculations, determine the missing number that will make the value of Expression B half the value of Expressi

on A. A (8 + 54 + 91) × 12 B (8 + 54 + 91) × _____ Enter your answer in the box.
Mathematics
1 answer:
Free_Kalibri [48]2 years ago
8 0

Answer:

6

Step-by-step explanation:

12÷2=6

Hope this helps! :)

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X is normally distributed with mean 250 and standard deviation 40. what value of x does only the top 15% exceed?
lubasha [3.4K]
The top 15% (85th percentile) is the cutoff value x such that

\mathbb P(X\le x)=\mathbb P\left(\dfrac{X-250}{40}\le\dfrac{x-250}{40}\right)=\mathbb P(Z\le z)=0.85

where z is the corresponding cutoff for the standardized normal distribution. We have z\approx1.0364, and so

\dfrac{x-250}{40}=z\implies x\approx291.456
3 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Gwar [14]

Answer:

The answer to your question is slope = 0; y = -2

Step-by-step explanation:

Data

A (-2, -2)

B (2, -2)

Process

1.- Calculate the slope

    m = (-2 - (-2)) / (2 - (-2))

    m = ( -2 + 2) / (2 + 2)

    m = 0/4

    m = 0

2.- The equation of the line is

    y - y1 = m(x- x1)

     y - (-2) = 0(x - (-2))

     y + 2 = 0

     y = -2

3 0
3 years ago
Lisa drinks 3 1/2 pints of milk a day. How much is this in cups?
olga nikolaevna [1]
7 cups; there are two cups per pint, so three and a half pints equals seven cups of milk.
5 0
3 years ago
What is your dream job?
soldi70 [24.7K]
My dream job? Well, I personally want to get accepted into Embry Riddle here in Arizona so that I can become a pilot, hopefully in the military. What about you? :)
8 0
3 years ago
Read 2 more answers
(1 point) Find two unit vectors orthogonal to a=⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩ Enter your answer so that the first no
Anni [7]

Answer:

 First vector

V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}

Second vector

V=- \dfrac{-15i+12j+4k}{\sqrt{385}}

Step-by-step explanation:

Given that

Vector a ,  a= 4 i + 5 j + 0 k

Vector b , b= 0 i + 1 j  - 3 k

The orthogonal vector V is given as

V = a x b

V is the cross product of the above two vector which is orthogonal to the vectors a and b.

V=\begin{vmatrix}i & j & k\\ 4 & 5 & 0\\  0& 1 &-3 \end{vmatrix}\\V=i(-15-0)-j(-12-0)+k(4-0)\\V=-15i+12j+4k

The unit vectors

V=\pm \dfrac{-15i+12j+4k}{\sqrt{15^2+12^2+4^2}}\\\\V=+\dfrac{-15i+12j+4k}{\sqrt{385}}\\V=-\dfrac{-15i+12j+4k}{\sqrt{385}}

First vector

V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}

Second vector

V=- \dfrac{-15i+12j+4k}{\sqrt{385}}

5 0
3 years ago
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