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yarga [219]
3 years ago
15

Simply your expression 4[(12-2) ²÷4]

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

100

Step-by-step explanation:

Simplify the following:

4 (12 - 2)^2/4

Hint: | Express 4 (12 - 2)^2/4 as a single fraction.

4 (12 - 2)^2/4 = (4 (12 - 2)^2)/4:

(4 (12 - 2)^2)/4

Hint: | Cancel common terms in the numerator and denominator of (4 (12 - 2)^2)/4.

(4 (12 - 2)^2)/4 = 4/4×(12 - 2)^2 = (12 - 2)^2:

(12 - 2)^2

Hint: | Subtract 2 from 12.

| 1 | 2

- | | 2

| 1 | 0:

10^2

Hint: | Evaluate 10^2.

| 1 | 0

× | 1 | 0

| 0 | 0

1 | 0 | 0

1 | 0 | 0:

Answer: 100

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  • Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
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Hence, {H1 , H2} are valid decomposition of G.

<h3>What is a Graph Decomposition?</h3>

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What is the solution to 39/45 - 2/3
julia-pushkina [17]

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The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a
AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal(\mu=460,\sigma^{2} =40^{2})

The z-score probability distribution for normal distribution is given by;

                               Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean time = 460 seconds

            \sigma = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

       P(X > x) = 0.10   {where x is the required time which boy need to beat}

       P( \frac{X-\mu}{\sigma} > \frac{x-460}{40} ) = 0.10

        P(Z > \frac{x-460}{40} ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em>                   </em>      \frac{x-460}{40} =1.2816

                         {x-460}{} =1.2816\times 40

<em>                           </em>x = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

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