Answer:
Part 15) The next three terms are 5/8,3/4 and 7/8
Part 16) The 37th term is -35.5
Step-by-step explanation:
we know that
In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant and this constant is called the common difference (d)
Part 15) Find the next three terms of the arithmetic sequence

so

The common difference is equal to
d=1/8
<u><em>Find the next three terms of the arithmetic sequence</em></u>
<u><em>Find a5</em></u>
----->
<u><em>Find a6</em></u>
----->
<u><em>Find a7</em></u>
----->
therefore
The next three terms are
5/8,3/4 and 7/8
Part 16) what is the 37th term of the arithmetic sequence

so


The common difference is equal to
d=-1.1
We can write an Arithmetic Sequence as a rule

substitute the values

For n=37
substitute



Answer:
Step-by-step explanation:
(x+2)(3x-3)
= 3x^2 -3x + 6x - 6
= 3x^2 + 3x - 6
Answer:
(-2, -8)
x = -2
y = -8
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
13x - 6y = 22
x = y + 6
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 13(y + 6) - 6y = 22
- Distribute 13: 13y + 78 - 6y = 22
- Combine like terms: 7y + 78 = 22
- Isolate <em>y</em> term: 7y = -56
- Isolate <em>y</em>: y = -8
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 6
- Substitute in <em>y</em>: x = -8 + 6
- Add: x = -2
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