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Elden [556K]
3 years ago
7

Find the slope and y intercept on the graph

Mathematics
1 answer:
igomit [66]3 years ago
8 0

Answer:

slope should more than likely be y = -2 + x = 1

Step-by-step explanation:

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Terri graphed a system of linear inequalities. Which ordered pairs are a part of the solution set for this system of linear ineq
Oduvanchick [21]

Answer: (2, -4) and (7, -1)

Step-by-step explanation:

Ok, the solutions of the system of inequalities are all the points that lie on the blue shaded part of the graph or in the solid line.

So, in order to see if the points are solutions of the system, then you need to locate the point in the graph and see if it is inside the shaded region or in the solid line (only in the segment that "touches" the shaded region).

Now, we want to find the equation of the solid line, we can see that it passes through the points (0, 6) and (6, 0)

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Then, in this case, the slope is:

a = (0 - 6)/(6 - 0) = -1.

And to find the value of b, we have that when x = 0, y = 6.

y = 6 = -1*0 + b

6 = b

The equation is:

y = -1*x + 6

(-1, 5) is not in the blue region nor in the solid line, so this is not a solution.

(7, - 1) this point is near the solid line, let's test it:

y(7) = -1*7 + 6 = -1

So the point (7, -1) is on the solid line, and is the other solution of the system.

8 0
4 years ago
PLEASE HELP LOTS OF POINTS
aleksandr82 [10.1K]
Plug in the to X value in
4 0
3 years ago
Read 2 more answers
A number decreased by 23 is 44.
xxMikexx [17]
If you add those two numbers together you get 67. 67-23=44 :)
5 0
3 years ago
Find an equivalent ratio.3:10
makvit [3.9K]
There are many answers. Here are some...

6:20
9:30
12:40
15:50
18:60
And so on. Count by threes for the first number and count by tens for the second number. :)
4 0
4 years ago
Read 2 more answers
1. Divide 6x^4 + 2x^3 – 6x^2 – 14x – 1 by 3x + 1 by using synthetic division or long division. Show all
iris [78.8K]
                  2x^3 - 2x - 4

3x + 1        6x^4 + 2x^3 - 6x^2 - 14x - 1
                  6x^4 + 2x^3
                
                                       -6x^2 - 14x - 1
                                       -6x^2 - 2x
     
                                                 -12x - 1
                                                 -12x - 4
 
                                                           3

3x + 1 is not a factor of the dividend because, dividing the dividend with 3x + 1 gives a remainder.
5 0
4 years ago
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