To figure out if the ordered pairs are a solution to the equations, you would need to plug in the points. Your points are ordered as (x,y)
You would plug in the number that's in the x spot in x, and the number in the y spot in y.
Let's start of with the first problem:
First thing you would do is plug in (-1) to x, and 6 to y.
Your equations would look like this:
6(-1) + 3(6) = 18
2(-1) + 6 = 7
What you would now do is solve the equations. When you solve them, you would get these answers
12 = 18
4 = 7
For #1, it would be no solution because the numbers do not equal each other. (Fun fact) If one of them ends up as a solution, but the other is no solution, the answer would be no solutions because BOTH of them have to be a solution to the equations given in order to be a solution.
If you do the same strategy, (plugging in the numbers to x and y), you would get the rest of the answers for the problems.
I hope this helps, if you need any more assistance, I would be glad to help!
Answer:
See below.
Step-by-step explanation:
Since sqrt(a) and sqrt(b) are in simplest radical form, that means a and b have no perfect square factors. When sqrt(a) and sqrt(b) are multiplied giving c * sqrt(d), the fact that c came out of the root means that there was c^2 inside the product sqrt(ab). This means that a and b have at least one common factor.
ab = c^2d
Example:
Let a = 6 and let b = 10.
sqrt(6) and sqrt(10) are in simplest radical form.
Now we multiply the radicals.
sqrt(a) * sqrt(b) = sqrt(6) * sqrt(10) = sqrt(60) = sqrt(4 * 15) = 2sqrt(15)
We have c = 2 and d = 15.
ab = c^2d
6 * 10 = 2^2 * 15
60 = 60
Our relationship between a, b and c, d works.
Answer:
what langue is that
Step-by-step explanation:
Answer:
See attachment for graph
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Step-by-step explanation:
Given
Required
Graph the relationship between both parameters
First, calculate the area;
This implies that: (2, 120) i.e. 2 cans for 120ft^2.
So we have:
(0,0) and (2,120)
(0,0) implies that: 0 cans for 0 square feet
Calculate the slope:
The equation is:
So, we have:
<em>See attachment for graph</em>
Hola! Intente resolverlo pero solo hice la primera por mi tiempo ahorita mismo y era:
f(0)=1
Toda la ecuación
