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3 years ago

PLSS HELP ME ASAP I WILL EVEN GIVE U BRAINLYEST BUT PLAA HELP ME!!

Mathematics

1 answer:

Ludmilka [50]3 years ago

4 0

Answer:

Complement of an Event: All outcomes that are NOT the event. So the Complement of an event is all the other outcomes (not the ones we want). And together the Event and its Complement make all possible outcomes.

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Which set of coordinates satisfies the equations x − 2y = -1 and 2x + 3y = 12? A. (1, 2) B. (3, 1) C. (3, 2) D. (-3, -2) E. (3,

Sindrei [870]

Answer:

(3,2) Choice C

Step-by-step explanation:

x-2y = -1

2x+3y =12

multiply the first equation by -2

-2x +4y = 2

add the 2 equations together

2x+3y =12

-2x +4y = 2

-----------------

7y =14

divide by 7

y =2

x-2y = -1

x -2(2) = -1

x-4 = -1

add 4 to each side

x = 3

(3,2)

5 0

4 years ago

Circle the equation that does not belong and explain why?

Andru [333]

It's either b or c I am not sure

7 0

4 years ago

Tell the answer of this please:<br> 5- {2*[(-5power2) -7 ] /3}

blondinia [14]

Answer:

-60

Step-by-step explanation:

Given the expression

5- {2*[(-5power2) -7 ] /3}

= 5- {2*[(25) -7 ] /3}

= 5- {2*[18 ] /3}

= -5 [2*6]

= -5(12)

= -60

Hence the required answer is -60

7 0

3 years ago

Sam spent $1.08 to make 18 copies at office max.At that rate how much will he pay to make 40 copies?

Alona [7]

Answer:

$2.40

Step-by-step explanation:

If we know it is $1.08 to make 18 copies. We can do the math to find the rate of 1 copy. This would be by doing 1.08/18=0.06. So, it costs $0.06 to make 1 copy. Now, multiply that by 40 copies 0.06x40=2.40. The cost of 40 copies is $2.40.

8 0

3 years ago

Read 2 more answers

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

lubasha [3.4K]

Answer:

a. 10.4 problems are expected to be resolved today, with a standard deviation of 1.44 problems.

b. 0.2457 = 24.57% probability 10 of the problems can be resolved today

c. 0.5137 = 51.37% probability 10 or 11 of the problems can be resolved today

d. 0.5017 = 50.17% probability more than 10 of the problems can be resolved today

Step-by-step explanation:

For each case, there are only two possible outcomes. Either they are solved, or they are not. Cases are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

It can resolve customer problems the same day they are reported in 80% of the cases.

This means that $p = 0.8$

Sample of 13 cases:

This means that $n = 13$

a. How many of the problems would you expect to be resolved today? What is the standard deviation?

Expected:

$E(X) = np = 13*0.8 = 10.4$

Standard deviation:

$\sqrt{V(X)} = \sqrt{13*0.8*0.2} = 1.44$

10.4 problems are expected to be resolved today, with a standard deviation of 1.44 problems.

b. What is the probability 10 of the problems can be resolved today?

This is $P(X = 10)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{13,10}.(0.8)^{10}.(0.2)^{3} = 0.2457$

0.2457 = 24.57% probability 10 of the problems can be resolved today.

c. What is the probability 10 or 11 of the problems can be resolved today?

This is $p = P(X = 10) + P(X = 11)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{13,10}.(0.8)^{10}.(0.2)^{3} = 0.2457$

$P(X = 11) = C_{13,11}.(0.8)^{11}.(0.2)^{2} = 0.2680$

$p = P(X = 10) + P(X = 11) = 0.2457 + 0.2680 = 0.5137$

0.5137 = 51.37% probability 10 or 11 of the problems can be resolved today.

d. What is the probability more than 10 of the problems can be resolved today?

This is

$P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{13,11}.(0.8)^{11}.(0.2)^{2} = 0.2680$

$P(X = 12) = C_{13,12}.(0.8)^{12}.(0.2)^{1} = 0.1787$

$P(X = 13) = C_{13,13}.(0.8)^{13}.(0.2)^{0} = 0.0550$

$P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) = 0.2680 + 0.1787 + 0.0550 = 0.5017$

0.5017 = 50.17% probability more than 10 of the problems can be resolved today

6 0

4 years ago