Answer:
C
Step-by-step explanation:
14 : 16
7 : 8
boys : girls
ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
It's equal to 1.6x10^(-8)
2 * (2a + b) + 8 = 4a + 2b + 8
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A. =
B. =
C. ≠ 4* (a + b + 2) = 4a + 4b + 8
D. =
Answer:
A. T, U
Step-by-step explanation:
T and U are stretched across the paper. the others seem a bit close or smaller to the size of X and Y, but when you look at T and U they seem longer than X an Y
Hope this helps!!! :)