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8090 [49]
3 years ago
14

Leading sculptors of Romantic era​

SAT
2 answers:
Softa [21]3 years ago
6 0
The great foremost Neoclassical sculptors were the great Italian Antonio Canova and the Dane Bertel Thorvaldsen. 3 Canova's their most greatest and most famous work of art may be Psyche Awakened by the Cupid's Kiss; he also produced awesome and great heroic statues of Napoleon. Thorvaldsen's foremost works may be Christ and Lion of Lucerne. Hope this helps! Mark brainliest please!
rodikova [14]3 years ago
3 0

Answer:

please give me brainlist and follow

Explanation:

The foremost Neoclassical sculptors were the Italian Antonio Canova and the Dane Bertel Thorvaldsen. 3 Canova's most famous work may be Psyche Awakened by Cupid's Kiss; he also produced heroic statues of Napoleon. Thorvaldsen's foremost works may be Christ and Lion of Lucerne.

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Pls help me, thank you!
Licemer1 [7]
I think it’s B


Hope it’s correct
6 0
3 years ago
Ms. Sanchez’s students were asked how many hours they spend participating in organized sports each week. Each row of the table r
slava [35]

The mean of a dataset is the average of the dataset.

The mean of the sample in the third row is 2.2

The dataset is given as:

5 5 3 0 6 2 2 4 5 2 3 4 3 0 1 4 0 4 3 6

From the complete question, the samples in the third row are:

Sample: 3 4 3 0 1

The mean of a dataset is calculated using:

\bar x = \frac{\sum x}{n}

Where:

n = 5 i.e. the number of samples

So, we have:

\bar x = \frac{3 + 4 + 3 + 0 + 1}{5}

Add the expressions in the numerator

\bar x = \frac{11}{5}

Divide 11 by 5

\bar x = 2.2

Hence, the mean of the sample in the third row is 2.2

Read more about mean at:

brainly.com/question/11887128

7 0
3 years ago
Read 2 more answers
A survey showed that 34 ​% of human resource professionals are at companies that rejected job candidates because of information
Svetllana [295]

Using the binomial distribution, it is found that since 16 is more than 2.5 standard deviations above the mean, it is a unusually high number.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

A measure is considered to be unusually high if it is more than 2.5 standard deviations above the mean.

In this problem, we hav ehtat:

  • 34% of companies reject candidates because of information found on their social media, hence p = 0.34.
  • 27 human resource professionals are randomly​ selected, hence n = 27.

Then, we find the threshold for unusually high values as follows:

E(X) = np = 27 x 0.34 = 9.18

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{27(0.34)(0.66)} = 2.46

T = 9.18 + 2 x 2.46 = 14.1.

Since 16 is more than 2.5 standard deviations above the mean, it is a unusually high number.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

3 0
2 years ago
If taxes are 20% of net income, what is the planned profit for the year?
kodGreya [7K]

Answer:Her return on investment is 20%

2. $40,000

Explanation:

4 0
2 years ago
QUESTION 9 / 10
Zina [86]
A. Opportunity cost is “the loss of potential gain from other alternatives when one alternative is chosen.” What you are losing is the chance for more money.
3 0
3 years ago
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