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2 years ago

Find the values of acts and why. Dragon drop the correct values in the box is below:

Mathematics

1 answer:

Vinvika [58]2 years ago

8 0

Answer:

This is a 30° x 60° x 90° triangle.

<u>The ratio of sides in same triangle:</u>

x : y : 10 = 1 : √3 : 2

x = 10/2 = 5

y = x√3 = 5√3

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What is the answer to this question?

melisa1 [442]

Answer: I think it is negative.

Step-by-step explanation: When you add a negative to a negative you still have a negative.

7 0

3 years ago

Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?

bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function $f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}$

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for $x=-6$ in the function and simplify the function.

Hence, let us substitute $x=-6$ in the function, we get,

$f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}$

Let us apply the rule $-\left(-a\right)=a$ , we get,

$f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}$

Multiplying the numbers, we get,

$f(-6)=\frac{100}{-10+e^{0.6}}$

The value of $e^{0.6}=1.822$

Substituting the value of $e^{0.6}=1.822$ , we get,

$f(-6)=\frac{100}{-10+1.822}$

Subtracting the denominator, we have,

$f(-6)=\frac{100}{-8.178}$

Dividing, we have,

$f(-6)=-12.228$

Rounding off to the nearest tenth, we have,

$f(-6)=-12.2$

Thus, the value of f(-6) is -12.2

4 0

2 years ago

Evaluate 4a + 7b + 3a − 2b for a = 5 and b = −3.

blsea [12.9K]

Answer:

Step-by-step explanation:

$4a+7b+3a-2b\qquad\text{combine like terms}\\\\=(4a+3a)+(7b-2b)\\\\=7a+5b\qquad\text{put a = 5 and b = -3 to the expression}\\\\7(5)+5(-3)=35-15=20$

5 0

2 years ago

What is 1 2/3 - (-5 2/3)

arsen [322]

Answer:

the answer is 7.33

Step-by-step explanation:

I used a calculator

6 0

1 year ago

Read 2 more answers

*WILL GIVE BRAINLIEST ANSWER* Analyze the graph. Determine what, if any, association there is. Explain. On a graph, points are g

Gnesinka [82]

Answer:

bro I thought someone else answered your question

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1 year ago