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2 years ago

If Sam bakes cookies at a rate of 35 per hour, at a constant rate, how many cookies can she bake in 12 hours?

Mathematics

1 answer:

dimaraw [331]2 years ago

5 0

Answer:

420

Step-by-step explanation:

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Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

8 0

3 years ago

Read 2 more answers

What is the slope of a line with the equation y=5x+2/5

igomit [66]

The slope-intercept form: y = mx + b

m - a slope

y = 5x + 2/5

Answer: The slope m = 5.

4 0

3 years ago

HELP LOOK AT THE SCREENSHOT<br><br> Find the value of x. (SHOW WORK)

Vanyuwa [196]

Answer: x = 2

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Explanation:

Refer to the diagram below.

I've added points D,E,F,G. This helps with labeling the segments and angles, and identifying the proper triangles (to see which are congruent pairs).

Triangle GEA is congruent to triangle GFA. We can prove this using the AAS congruence theorem. We have AG = AG as the pair of congruent sides, and the congruent pairs of angles are marked in the diagram (specifically the blue pairs of angles and the gray right angle markers)

Since triangle GEA is congruent to triangle GFA, this means the corresponding pieces segment GF and GE are the same length.

The diagram shows GF = 3x-4, so this means GE = 3x-4 as well.

----------------------

Through similar steps, we can show that triangle GEC is congruent to triangle GDC. We also use AAS here as well.

The congruent triangles lead to GD = GE. So GD = 3x-4. The diagram shows that GD = 6x-10

Since GD is equal to both 3x-4 and 6x-10, this must mean the two expressions are equal.

----------------------

Now let's solve for x

6x-10 = 3x-4

6x-3x = -4+10

3x = 6

x = 6/3