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2 years ago

How to do these answers get marked as brainliest!

Mathematics

1 answer:

const2013 [10]2 years ago

6 0

Answer:

8. twenty-three multiplied by f.

10. Five times the number x is equal to 8 .

12. the product of 3 and a number divided by 7'.

14. The product of the difference of two times a number and 7 and four.

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Whats 4/58 I need help pls I have no calculator. Pls pls pls tell me

Anon25 [30]

Answer:

2/29 or 0.06896551724

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Make a table of 4 additional speeds equivalent to 50 miles per hour.

Nostrana [21]

Answer:

80.4672kmh

22.352m/s

43.4488 knots

73.3333 fps

Step-by-step explanation:

8 0

3 years ago

If the square root of 61 is the longest side length in the triangle and the shorter sides are x and x+1, find the value of x tha

Tju [1.3M]

Answer:

x = 5

Step-by-step explanation:

You want to find x such that ...

x^2 +(x +1)^2 = 61

2x^2 +2x -60 = 0 . . . . . simplify, subtract 61

x^2 +x -30 = 0 . . . . . . . divide by 2

(x +6)(x -5) = 0 . . . . . . . . factor; solutions will make the factors be zero.

The relevant solution is x = 5.

5 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

You invest $720 in an account that has an annual interest rate of 6.2%, compounded semiannually. How much money will be in the a

sladkih [1.3K]

Answer:

$929.66

Step-by-step explanation: I hope this helps

You would have to estimate this to about 930 if to the nearest integer. <3

5 0

3 years ago

Read 2 more answers