Answer:
Step-by-step explanation:
Some facts to establish before we try to solve: 
and another way of writing 
is 
. Also order of operations: PEMDAS
For the first option:
We solve what is in the parenthesis: 2*2=4*2=8*2=16*2=32*2=64 so , which is another way to write
For the second option: If the square root of 64 is 8, the there is no way we can multiply another value by it.
The third option: When dealing with square roots, we can solve the inside first and then take the square root:
definitely not 64 (though if you're curious it's 4096)
The fourth: Another way to write the square root is to raise the value to the 1/2 power so
Which is the same as
Fifth: Like the third, we solve the inside of the square root first
16*4= 64 and then
Sixth: We need a nice whole number (8), and 
has no clean roots, so its result will have decimals. It can't be our answer
Answer:
see explanation
Step-by-step explanation:
Given
9n² - n - 
= 0 ← multiply through by 3 to clear the fraction
27n² - 3n - 2 = 0 ← factoring
Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term
product = 27 × - 2 = - 54 and sum = - 3
The factors are - 9 and + 6
Use these factors to split the n- term
27n² - 9n + 6n - 2 = 0 ( factor the first/second and third/fourth terms )
9n(3n - 1) + 2(3n - 1) = 0 ← factor out (3n - 1) from each term
(3n - 1)(9n + 2) = 0
Equate each factor to zero and solve for n
3n - 1 = 0 ⇒ 3n = 1 ⇒ n = 
9n + 2 = 0 ⇒ 9n = - 2 ⇒ n = - 
Answer:
23.15 an hour
Step-by-step explanation:
1. B
2. D I'm not sure about this one
3. A
4. C
5. C
6. B
7. -9
8. 1
9. -2
10. 5
Hope this helps! I'm sure about all except for number 2!
have an arithmetic sequence here....to find the common difference, subtract the first term from the second term. 13 - 3 = 10...so basically, ur adding 10 to each number to get to the next number.
before we find s5, we r going to find a5...because we need a5 to use in the sum formula.....a5 is the fifth term, and it is 43
sn = (n (a1 + a5) / 2
s5 = (5 (3 + 43) / 2
s5 = (5 (46)) / 2
s5 = 230/2
s5 = 115 <===
or, for this particular problem, s5 is the sum of the first 5 terms.
3 + 13 + 23 + 33 + 43 = 115.....u can do it this way for s5...but if u were asked to find s20, I suggest using the formula.
