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2 years ago

6

Y = (2/3)x - 1 y = -x + 4

1 answer:

Vinil7 [7]2 years ago

7 0

Are these two separate questions?

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The length of a rectangle is (3x − 5) inches, and its width is 2x inches. Find the area of the rectangle. Hint: Area of a rectan

Dvinal [7]

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2 years ago

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Helppppppop me I’m need help on this nowwwwee difnoxdnslsbsk

Aleks04 [339]

Answer:

a=3, b=3, c=5

Step-by-step explanation:

4 $\frac{1}{2}$ ÷1 $\frac{1}{4}$ =a $\frac{b}{c}$

= $\frac{9}{2}$ ÷ $\frac{5}{4}$

= $\frac{9}{2}$ × $\frac{4}{5}$

= $\frac{36}{10}$

=3 $\frac{6}{10}$

=3 $\frac{3}{5}$

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3 years ago

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3 years ago

A chef buys 6 pounds of salmon for $51. How much will he pay for 9 pounds of salmon?

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$76.5

51/6 = 8.5
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2 years ago

Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB

Digiron [165]

Answer: The distace between midpoints of AP and QB is $\frac{a}{8}$ .

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = $\frac{AP}{2}$

QB = $\frac{AP}{2}$

Substituing:

AP + 2*( $\frac{AP}{2}$ ) = a

2AP = a

AP = $\frac{a}{2}$

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = $\frac{AP}{2}$

QB = $\frac{a}{2}*\frac{1}{2}$

QB = $\frac{a}{4}$

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

$\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}$

$\frac{AP}{2} = \frac{a}{4}$

<u>Midpoint of QB</u>:

$\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}$

$\frac{QB}{2} = \frac{a}{8}$

The distance is:

d = $\frac{a}{4} - \frac{a}{8}$

d = $\frac{a}{8}$

4 0

2 years ago