Answer:
R ≈ 8.31
Step-by-step explanation:
Filling in the given values ...
... pV = nRT
... 2·4.155 = 1·R·1
... 8.31 = R
Answer:
- 3, - 1, 1
Step-by-step explanation:
To find the first 3 terms substitute n = 1, 2, 3 into the formula
a₁ = 2(1) - 5 = 2 - 5 = - 3
a₂ = 2(2) - 5 = 4 - 5 = - 1
a₃ = 2(3) - 5 = 6 - 5 = 1
The first 3 terms are - 3, - 1, 1
Answer:
see below
Step-by-step explanation:
<h3>Given</h3>
- Distance is 142.2 m, correct to 1 decimal place
- Time is 7 seconds, correct to nearest second
<h3>To find:</h3>
- Upper bound for the speed
<h3>Solution </h3>
<em>Upper bound for the speed = upper bound for distance/lower bound for time</em>
- Upper bound for distance = 142.25 m (added 0.1/5 = 0.05)
- Lower bound for time = 6.5 seconds (subtracted 1/2 = 0.5)
<u>Then, the speed is:</u>
- 142.25/6.5 = 21.88 m/s
- 21.88 = 21.9 m/s correct to 1 decimal place
- 21.88 = 22 m/s correct to nearest m/s
The answer would be 3. {0,3}.
Remember: {x,y}
2(0)+3=3
0+3=3
0+3=3
Answer:
the number of protons in the nuclues of an atom
