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3 years ago

7

I dont get angles at all

1 answer:

Free_Kalibri [48]3 years ago

7 0

Answer:

The picture is not clear.

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Integrate sin²2x cos²2x dx

DochEvi [55]

$\sin^2x=\dfrac{1-\cos2x}2$
$\cos^2x=\dfrac{1+\cos2x}2$

From the identities above, you have

$\sin^22x\cos^22x=\dfrac{(1-\cos4x)(1+\cos4x)}4=\dfrac{1-\cos^24x}4$

Applying once more, you have

$\dfrac{1-\cos^24x}4=\dfrac{1-\dfrac{1+\cos8x}2}4=\dfrac{1-\cos8x}8$

So,

$\displaystyle\int\sin^22x\cos^22x\,\mathrm dx=\frac18\int(1-\cos8x)\,\mathrm dx=\frac x8-\frac1{64}\sin8x+C$

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3 years ago

In a pack of pretzel sticks, one-quarter of the total number of pretzel sticks is 14.

DanielleElmas [232]

Answer:

6 lol have a good day

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Mashcka [7]

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3 years ago

Please help me I dont get this question

alisha [4.7K]

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During a cold night in Chicago, the temperature each day at midnight was -6.5 degrees, -10.7 degrees, -2.3 degrees, -4.5 degrees

galina1969 [7]

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Step-by-step explanation:

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3 years ago