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NemiM [27]
3 years ago
8

Staples recently charged $3.79 per ream (package of 500 sheets) of regular paper and $5.49 per ream of paper made of recycled fi

bers. last semester, valley collage spent $582.44 for 116 reams of paper. how many of each type were purchased?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0
<h3>Given</h3>

regular paper costs $3.79 per ream

recycled paper costs $5.49 per ream

$582.44 was spent for 116 reams

<h3>Find</h3>

the numbers of reams of each type that were purchased

<h3>Solution</h3>

Let r and g represent the numbers of reams of regular and recycled ("green") paper, respectively.

... r + g = 116 . . . . . . . . 116 reams were purchased

... 3.79r + 5.49g = 582.44 . . . . this is the total cost of the purchase

Solve the first equation for r and substitute that into the second equation.

... r = 116 - g

... 3.79(116 - g) + 5.49g = 582.44 . . . . . use the expression for r

... 1.70g + 439.64 = 582.44 . . . . . . . . . simplify

... g = (582.44 -439.64)/1.70 = 84 . . . . subtract the constant, divide by 1.70

... r = 116 -84 = 32 . . . . . . . . . . . . . . . . . use the equation for r

32 regular reams and 84 recycled reams were purchased

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
MATH HELP PLEASE!!! PLEASE HELP!!!
grandymaker [24]
The answer is:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
________________________________________________________

Explanation:

________________________________________________________
Given the original function:  

" c(y) = (5/9) (x <span>− 32) " ; in which "x = f" ; and "y = c(f) " ;
________________________________________________________
</span>→  <span>Write the original function as:  " y = </span>(5/9) (x − 32) " ; 

Now, change the "y" to an "x" ; and the "x" to a "y"; and rewrite; as follows:
________________________________________________________
    x = (5/9) (y − 32) ; 

Now, rewrite THIS equation; by solving for "y" ; in terms of "x" ; 
_____________________________________________________
→ That is, solve this equation for "y" ; with "c" as an "isolated variable" on the
 "left-hand side" of the equation:

We have:

→  x  =  " (  \frac{5}{9}  ) * (y − 32) " ;

Let us simplify the "right-hand side" of the equation:
_____________________________________________________

Note the "distributive property" of multiplication:
__________________________________________
a(b + c) = ab + ac ;  <u><em>AND</em></u>:

a(b – c) = ab – ac
.
__________________________________________

As such:
__________________________________________

" (\frac{5}{9}) * (y − 32) " ; 

=  [ (\frac{5}{9}) * y ]   −  [ (\frac{5}{9}) * (32) ] ; 


=  [ (\frac{5}{9}) y ]  − [ (\frac{5}{9}) * (\frac{32}{1})" ;

=  [ (\frac{5}{9}) y ]  − [ (\frac{(5*32)}{(9*1)} ] ; 

=  [ (\frac{5}{9}) y ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ (\frac{5y}{9}) ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ \frac{(5y-160)}{9} ] ;  
_______________________________________________
And rewrite as:  

→  " x  =  \frac{(5y-160)}{9} "  ;

We want to rewrite this; solving for "y";  with "y" isolated as a "single variable" on the "left-hand side" of the equation ;

We have:

→  " x  =  \frac{(5y-160)}{9} "  ; 

↔  " \frac{(5y-160)}{9} = x ; 

Multiply both sides of the equation by "9" ; 

 9 * \frac{(5y-160)}{9}  =  x * 9 ; 

to get:

→  5y − 160 = 9x ; 

Now, add "160" to each side of the equation; as follows:
_______________________________________________________

→  5y − 160 + 160 = 9x + 160 ; 

to get:

→  5y  =  9x + 160 ; 

Now,  divided Each side of the equation by "5" ; 
      to isolate "y" on one side of the equation; & to solve for "y" ; 

→  5y / 5  = (9y + 160) / 5 ; 

to get: 
 
→  y = (9/5)x + (160/5) ; 

→  y =  (9/5)x + 32 ; 

 →  Now, remember we had substituted:  "y" for "c(f)" ; 

Now that we have the "equation for the inverse" ;
     →  which is:  " (9/5)x  + 32" ; 

Remember that for the original ("non-inverse" equation);  "y" was used in place of "c(f)" .  We have the "inverse equation";  so we can denote this "inverse function" ; that is, the "inverse" of "c(f)" as:  "f(c)" .

Note that "x = c" ; 
_____________________________________________________
So, the inverse function is: "  f(c) = (9/5) c  + 32 " .
_____________________________________________________

 The answer is:  " f(c) = \frac{9}{5} c  + 32 " ;
_____________________________________________________
 →  which is:  

→  Answer choice:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
_____________________________________________________
6 0
3 years ago
Complete the equation of the line whose y-intercept is (0.-1) and slope is 4.
meriva
Well just by looking at the information provided, you can tell that the equation would look like y = 4x -1. The y-intercept is -1 because the x value is 0. But if you want to see how to solve it algebraically, here’s an explanation... You need to substitute the y-intercept into the equation in order to solve for b, which would then complete the equation. Take the equation y=mx+b. Substitute in the slope and xy values, (-1) = 4(0) + b. Now the equation should look like this: -1 = b. So now that you have the value of b, the complete equation should be y=4x-1
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3 years ago
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