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2 years ago

Find x, round to the nearest tenth degree.

Mathematics

1 answer:

Romashka [77]2 years ago

5 0

Answer:

Step-by-step explanation:

Use the Law of Cosines

A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°

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1/6d + 2/3 = 1/4(d-2)

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$\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \\ \frac{d}{6}^{(2}}+\frac{2}{3}^{(4}=\frac{d-2}{4}^{(3} \\ \\ 2d+8=3(d-2) \\ \\ 2d+8=3d-6 \\ \\ 2d-3d=-6-8 \\ \\ -d=-14 \\ \\ \boxed{d=14}$

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2 years ago

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dimaraw [331]

Answer:

2;4;3

Step-by-step explanation:

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2 years ago

Solve 3x - 9x + 7 - 3 = -8.

melamori03 [73]

Answer:

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Step-by-step explanation:

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3 years ago

A rectangle is inscribed in a right isosceles triangle, such that two of its vertices lie on the hypotenuse, and two other on th

Rufina [12.5K]

Answer:

Part 1) The base is $25\ in$ and the height is $10\ in$

Part 2) The base is $7.5\ in$ and the height is $18.75\ in$

Step-by-step explanation:

case 1) Right isosceles triangle of the left

Let

x------> the base of the rectangle

y----> the height of the rectangle

Remember that

In a right isosceles triangle the lengths of the legs of the triangle is the same

$y+x+y=45$

$2y+x=45$ ----> equation A

$\frac{x}{y} =\frac{5}{2}$

$x=2.5y$ -----> equation B

substitute equation B in the equation A

$2y+2.5y=45$

$4.5y=45$

$y=10\ in$

Find the value of x

$x=2.5(10)=25\ in$

case 2) Right isosceles triangle of the right

Let

x------> the base of the rectangle

y----> the height of the rectangle

Remember that

In a right isosceles triangle the lengths of the legs of the triangle is the same

$y+x+y=45$

$2y+x=45$ ----> equation A

$\frac{y}{x} =\frac{5}{2}$

$y=2.5x$ -----> equation B

substitute equation B in the equation A

$2(2.5x)+x=45$

$6x=45$

$x=7.5\ in$

Find the value of y

$y=2.5(7.5)=18.75\ in$

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2 years ago

PLEASE HELP FOR BRAINLIEST!!!

SOVA2 [1]

The measure of an angle formed by a secant and a tangent drawn from a point outside the circle is half the the difference of the intercepted arcs.

 $21^o= \frac{arc \ RU-arc \ SU}{2}= \frac{119^o-arc \ SU}{2} \ \to \ \\ \\ 42= 119-arcSU \\ arc \ SU=119-42=77^o$

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2 years ago