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2 years ago

Find x, round to the nearest tenth degree.

Mathematics

1 answer:

Romashka [77]2 years ago

5 0

Answer:

Step-by-step explanation:

Use the Law of Cosines

A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°

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A bookkeeper bought 2,000 exercise book distributed 200 books to the student from poor economic background as donation .he sold

Andrews [41]

Books left=2000-200=1800

ATQ

$\\ \sf\longmapsto 1800x+10=0.08x$

$\\ \sf\longmapsto 1800x-0.08x=-10$

$\\ \sf\longmapsto x(1800-0.08)=-10$

$\\ \sf\longmapsto x(1799.92)=-10$

$\\ \sf\longmapsto x=|\dfrac{10}{1799.92}|$

$\\ \sf\longmapsto x=0.005$

Now

$\\ \sf\longmapsto CP=0.005(2000)=10$

6 0

2 years ago

Help please I really need help

Tems11 [23]

Answer:

Step-by-step explanation:

7 0

3 years ago

Please help me thx

anyanavicka [17]

The answer is Y=1/26x-2

5 0

2 years ago

Read 2 more answers

Plz help memenememdme

Harrizon [31]

1-d
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4 0

3 years ago

If you graph 2y+8=6x^2-10x what will be the y intercept?

Rufina [12.5K]

Answer:

Y intercept will be -4.

Step-by-step explanation:

Here we are given our function as

$2y+8=6x^2-10x$

We are asked to determine the y intercept.

The y intercept is the y ordinate of the coordinates of the point at which the graph of the function intersects the y axis.

Please note that the point at which graph cuts the y axis have x=0

Hence in order to determine y intercept we need to put x=0 in our function and solve it for y :

$2y+8=6x^2-10x2y+8=6x^2-10x$

Putting x =0

$2y+8=6x^2-10x2y+8=6(0)^2-10(0)$

$2y+8=6x^2-10x2y+8=0-10(0)$

$2y+8=6x^2-10x2y+8=0$

subtracting both sides by 8

$2y+8=6x^2-10x2y=-8$

dividing both sides by 2

=-4

8 0

3 years ago