H=1/3+1/60d,d=R Hope this is correct.
Answer:
E. 1,700 is your answer.
Step-by-step explanation:
What you do is you add 668 + 575 + 453 together.
668 + 575 + 453 = 1,696.
The hundreds place is the 9. Since the 9 is bigger than 4 it gets rounded up. That means the 6 in front of the 9 becomes a 7 and 9 and 6 become a zero.
E. 1,700 is your answer.
Answer:
t^-12
Step-by-step explanation:
you multiply the -2 and 6.
Answer and Explanation:
Solution: The operation of concatenation for a set of string on p. and the set is
AB = {XY | X ∈ A and y ∈ B}.
We need to satisfy all these following properties to find out the standard set is closed under concatenation.
1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.
2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.
3- Intersection of two standards set A and B is A∩B is also a regular set member.
4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.
The closure of the regular set is also standard, and the concatenation of traditional sets is regular.
Answer:
Its 0, 1.
Step-by-step explanation:
ItsQuipo on yt
